'FormHelper' 对象在 django 中使用脆皮表单时没有属性 'append'

Question

我是 Django 的新手，我正在尝试用脆脆的形式来设计表单。我的应用程序中有一个表单，它恰好是一个模型表单，我已经按照这里所说的/sf/answers/924111191/使 ModelForm 与脆皮表单一起工作，但收到此错误：

'FormHelper' object has no attribute 'append'

这是我的代码的外观forms.py：

from django import forms
from models import Ticket, Ticketuser
from crispy_forms.helper import FormHelper
from crispy_forms.layout import Submit, Layout, Fieldset, ButtonHolder
from crispy_forms.bootstrap import FormActions

class AddTicketForm(forms.ModelForm):

  def __init__(self, *args, **kwargs):
    super(AddTicketForm, self).__init__(*args, **kwargs)
    self.helper = FormHelper(self)
    self.helper.append(Submit('save', 'save'))

  class Meta:
    model = Ticket
    fields = ('id', 'comment')

  def process(self):
    data = self.cleaned_data
    data = data['comment']
    return data

如何克服这个问题并像我想要的那样设计表单？

Answer 1

显然，表单助手 api 已更改，您需要使用add_input而不是append现在：

这是直接来自文档的示例：

from crispy_forms.helper import FormHelper
from crispy_forms.layout import Submit

class ExampleForm(forms.Form):
    [...]
    def __init__(self, *args, **kwargs):
        super(ExampleForm, self).__init__(*args, **kwargs)
        self.helper = FormHelper()
        self.helper.form_id = 'id-exampleForm'
        self.helper.form_class = 'blueForms'
        self.helper.form_method = 'post'
        self.helper.form_action = 'submit_survey'

        self.helper.add_input(Submit('submit', 'Submit'))