如何将mysql表行转换为列

dmi*_*er1 16 mysql sql pivot

这是我当前的mysql表的样子:

PunchID EmpID   PunchEvent  PunchDateTime
1       0456    clockin     5/14/2013 8:36:26 AM
48      0456    breakout    5/14/2013 12:01:29 PM
53      0456    breakin     5/14/2013 12:28:31 PM
54      0456    clockout    5/14/2013 2:28:33 PM
57      0456    clockin     5/15/2013 7:38:34 AM
58      0456    breakout    5/15/2013 7:38:39 AM
59      0456    breakin     5/15/2013 7:38:41 AM
60      0456    clockout    5/15/2013 7:38:42 AM
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现在我想返回一个基于星期几分组的结果集,如下所示:

Day       ClockIn      BreakOut    BreakIn      ClockOut
Tuesday   8:36:26 AM  12:01:29 PM  12:28:31 PM  2:28:33 PM
Wednesday 7:38:34 AM  etc, etc...
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这是我目前的查询.但它只返回每天的第一拳.

SELECT DATE_FORMAT(PunchDateTime, '%W') as day, PunchEvent, DATE_FORMAT(PunchDateTime, '%l:%m:%s %p') as time FROM timeclock_punchlog WHERE EmpID = '0456' GROUP BY DATE(PunchDateTime) ORDER BY PunchDateTime ASC;
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有人可以帮我弄这个吗?谢谢迈克

Joh*_*Woo 37

SELECT  DATE_FORMAT(PunchDateTime, '%W') DAY,
        MAX(CASE WHEN PunchEvent = 'ClockIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockIn,
        MAX(CASE WHEN PunchEvent = 'BreakOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakOut,
        MAX(CASE WHEN PunchEvent = 'BreakIn' THEN DATE_FORMAT(PunchDateTime, '%r') END) BreakIn,
        MAX(CASE WHEN PunchEvent = 'ClockOut' THEN DATE_FORMAT(PunchDateTime, '%r') END) ClockOut
FROM    tableName
WHERE   EmpID = 456
GROUP   BY DATE_FORMAT(PunchDateTime, '%W')
ORDER   BY PunchDateTime
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OUTPUT

?????????????????????????????????????????????????????????????????????
?    DAY    ?   CLOCKIN   ?  BREAKOUT   ?   BREAKIN   ?  CLOCKOUT   ?
?????????????????????????????????????????????????????????????????????
? Tuesday   ? 08:36:26 AM ? 12:01:29 PM ? 12:28:31 PM ? 02:28:33 PM ?
? Wednesday ? 07:38:34 AM ? 07:38:39 AM ? 07:38:41 AM ? 07:38:42 AM ?
?????????????????????????????????????????????????????????????????????
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