合并行并将其值相加

Raf*_*ael 5 aggregate r

下面是我原始数据框的一小部分.我需要那些在特定的行合并id是在特定的季节重复和licvessel是不同的.通过结合我需要总和qttygrossTon.

请以id 431中的season 1998为例(*).

season   lic     id  qtty   vessel   grossTon
…   
1998    16350   431  40     435       57
1998    16353   431  28     303       22.54
…   
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同一主题431有两种不同的lic(16350和16353)和两种不同的vessels(435和303).在这个特定情况下预期的结果是:

  season     lic       id   qtty  vessel    grossTon
    …
    1998    16350      431   68     435     79.54
    …
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我不介意它licvessel生成的行中提醒,我要的是保持season,id并将得到的总和qttygrossTon.在上面的示例中,我手动选择lic 16350vessel 435.

说实话,我不知道该怎么做,所以我非常感谢任何帮助.

谢谢

原始数据(*=要组合的行)

season  lic id  qtty    vessel  grossTon
1998    15593   411 40  2643    31.5
1999    27271   411 40  2643    31.5
2000    35758   411 40  2643    31.5
2001    45047   411 50  2643    31.5
2002    56291   411 55  2643    31.5
2003    66991   411 55  2643    31.5
2004    80581   411 55  2643    31.5
2005    95058   411 52  NA  NA
2006    113379  411 50  10911   4.65
2007    120894  411 50  10911   4.65
2008    130033  411 50  2483    8.5
2009    139201  411 46  2296    50
2010    148833  411 46  2296    50
2011    158395  411 46  2296    50
1998    16350   431 40  435 57    # *
1998    16353   431 28  303 22.54 # *
2000    37491   436 50  2021    19.11
2001    47019   436 50  2021    19.11
2002    57588   436 51  2021    19.11
2003    69128   436 51  2021    19.11
2004    82400   436 52  2021    19.11
2005    95599   436 50  2021    19.11
2006    113126  436 50  2021    19.11
2007    122387  436 50  2021    19.11
2008    131126  436 50  2021    19.11
2009    140417  436 50  2021    19.11
2010    150673  436 50  2021    19.11
2011    159776  436 50  2021    19.11
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另外,我需要保留前一行和后续行,id每季只有一行.像这样:(*=组合后产生的行)

 season lic id  qtty    vessel  grossTon
1998    15593   411 40  2643    31.5
1999    27271   411 40  2643    31.5
2000    35758   411 40  2643    31.5
2001    45047   411 50  2643    31.5
2002    56291   411 55  2643    31.5
2003    66991   411 55  2643    31.5
2004    80581   411 55  2643    31.5
2005    95058   411 52  NA  NA
2006    113379  411 50  10911   4.65
2007    120894  411 50  10911   4.65
2008    130033  411 50  2483    8.5
2009    139201  411 46  2296    50
2010    148833  411 46  2296    50
2011    158395  411 46  2296    50
1998    16350   431 68  435 79.54 #*
2000    37491   436 50  2021    19.11
2001    47019   436 50  2021    19.11
2002    57588   436 51  2021    19.11
2003    69128   436 51  2021    19.11
2004    82400   436 52  2021    19.11
2005    95599   436 50  2021    19.11
2006    113126  436 50  2021    19.11
2007    122387  436 50  2021    19.11
2008    131126  436 50  2021    19.11
2009    140417  436 50  2021    19.11
2010    150673  436 50  2021    19.11
2011    159776  436 50  2021    19.11
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Ric*_*rta 12

如果将data.frame转换为data.table,则可以充分利用该by参数

library(data.table)

DT <- data.table(DF)  # DF is your original data
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那么它只是一行:

DT[, lapply(.SD, sum), by=list(season, lic, id, vessel)]
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我们可以过滤掉1998 Season,如果我们愿意的话:'

DT[, lapply(.SD, sum), by=list(season, lic, id, vessel)][season==1998]
   season   lic  id vessel qtty grossTon
1:   1998 15593 411   2643   40    31.50
2:   1998 16350 431    435   68   114.00
3:   1998 16353 431    303   68    45.08
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整个结果输出如下所示:

    season    lic  id vessel qtty grossTon
 1:   1998  15593 411   2643   40    31.50
 2:   1999  27271 411   2643   40    31.50
 3:   2000  35758 411   2643   40    31.50
 4:   2001  45047 411   2643   50    31.50
 5:   2002  56291 411   2643   55    31.50
 6:   2003  66991 411   2643   55    31.50
 7:   2004  80581 411   2643   55    31.50
 8:   2005  95058 411     NA   52       NA
 9:   2006 113379 411  10911   50     4.65
10:   2007 120894 411  10911   50     4.65
11:   2008 130033 411   2483   50     8.50
12:   2009 139201 411   2296   46    50.00
13:   2010 148833 411   2296   46    50.00
14:   2011 158395 411   2296   46    50.00
15:   1998  16350 431    435   68   114.00
16:   1998  16353 431    303   68    45.08
17:   1999  28641 431    303   68    45.08
18:   1999  28644 431    435   68   114.00
19:   2000  37491 436   2021   50    19.11
20:   2001  47019 436   2021   50    19.11
21:   2002  57588 436   2021   51    19.11
22:   2003  69128 436   2021   51    19.11
23:   2004  82400 436   2021   52    19.11
24:   2005  95599 436   2021   50    19.11
25:   2006 113126 436   2021   50    19.11
26:   2007 122387 436   2021   50    19.11
27:   2008 131126 436   2021   50    19.11
28:   2009 140417 436   2021   50    19.11
29:   2010 150673 436   2021   50    19.11
30:   2011 159776 436   2021   50    19.11
    season    lic  id vessel qtty grossTon
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Ben*_*Ben 5

以下是Frank建议使用的单行基本解决方案aggregate

Df_agg <- aggregate(. ~  season + lic + id + vessel, data = DF, sum)
# DF is your data
# we use season + lic + id + vessel as the grouping elements
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检查输出:

Df_agg[with(Df_agg, order(lic)), ] 
# check the output (sort for convenience), identical to Ricardo Saporta's output
   season    lic  id vessel qtty grossTon
21   1998  15593 411   2643   40    31.50
3    1998  16350 431    435   68   114.00
1    1998  16353 431    303   68    45.08
22   1999  27271 411   2643   40    31.50
2    1999  28641 431    303   68    45.08
4    1999  28644 431    435   68   114.00
23   2000  35758 411   2643   40    31.50
5    2000  37491 436   2021   50    19.11
24   2001  45047 411   2643   50    31.50
6    2001  47019 436   2021   50    19.11
25   2002  56291 411   2643   55    31.50
7    2002  57588 436   2021   51    19.11
26   2003  66991 411   2643   55    31.50
8    2003  69128 436   2021   51    19.11
27   2004  80581 411   2643   55    31.50
9    2004  82400 436   2021   52    19.11
10   2005  95599 436   2021   50    19.11
11   2006 113126 436   2021   50    19.11
28   2006 113379 411  10911   50     4.65
29   2007 120894 411  10911   50     4.65
12   2007 122387 436   2021   50    19.11
20   2008 130033 411   2483   50     8.50
13   2008 131126 436   2021   50    19.11
17   2009 139201 411   2296   46    50.00
14   2009 140417 436   2021   50    19.11
18   2010 148833 411   2296   46    50.00
15   2010 150673 436   2021   50    19.11
19   2011 158395 411   2296   46    50.00
16   2011 159776 436   2021   50    19.11
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检查1998年,与RS一样,似乎OP的期望输出中有错误,57 + 57!= 79.54但= 114

Df_agg[Df_agg$season == 1998,]

   season   lic  id vessel qtty grossTon
21   1998 15593 411   2643   40    31.50
3    1998 16350 431    435   68   114.00
1    1998 16353 431    303   68    45.08
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