如何上传文件并将其保存到Stream以便使用C#进一步预览？

Question

有没有办法上传文件,将其保存到Stream,这个Stream我会暂时保存在Session中,最后,我会尝试预览这个Session中的上传文件？

例如,pdf文件.

谢谢!!

EDITED

这是我正在尝试做的事情:

HttpPostedFileBase hpf = Request.Files[0] as HttpPostedFileBase;
byte[] buffer = new byte[hpf.InputStream.Length];
MemoryStream ms = new MemoryStream(buffer);
ms.Read(buffer, 0, (int)ms.Length);
Session["pdf"] = ms.ToArray();
ms.Close();

在另一种方法中,我这样做:

byte[] imageByte = null;

imageByte = (byte[])Session["pdf"];

Response.ContentType = "application/pdf";
Response.Buffer = true;
Response.Clear();
Response.BinaryWrite(imageByte);

但没有任何事情发生...我的浏览器甚至打开一个nem页面来显示pdf文件,但是会显示一个窗口,说该文件不是pdf(或者文件不是用pdf启动的,我不明白那)

Answer 1

当然可以.我在我的应用程序中将文件(PDF /图像)上传到我的数据库.我的模型对象实际上将文件存储为字节数组,但对于我必须转换为流和从流转换的其他函数,所以我确保它以流格式保存它也很容易.

以下是我的应用程序中的一些代码示例(复制n粘贴)

在File我使用走动的文件(PDF文件/图片)对象:

public class File : CustomValidation, IModelBusinessObject
{
    public int ID { get; set; }
    public string MimeType { get; set; }
    public byte[] Data { get; set; }
    public int Length { get; set; }
    public string MD5Hash { get; set; }
    public string UploadFileName { get; set; }
}

.. PdfDoc专门用于PDF文件的类型:

public class PdfDoc : File
{
    public int ID { get; set; }
    public int FileID
    {
        get { return base.ID; }
        set { base.ID = value; }
    }
    [StringLength(200, ErrorMessage = "The Link Text must not be longer than 200 characters")]
    public string LinkText { get; set; }


    public PdfDoc() { }

    public PdfDoc(File file)
    {
        MimeType = file.MimeType;
        Data = file.Data;
        Length = file.Length;
        MD5Hash = file.MD5Hash;
        UploadFileName = file.UploadFileName;
    }

    public PdfDoc(File file, string linkText)
    {
        MimeType = file.MimeType;
        Data = file.Data;
        Length = file.Length;
        MD5Hash = file.MD5Hash;
        UploadFileName = file.UploadFileName;

        LinkText = linkText;
    }
}

..一个接收多部分POST以进行文件上传的操作示例:

    //
    // POST: /Announcements/UploadPdfToAnnouncement/ID
    [KsisAuthorize(Roles = "Admin, Announcements")]
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult UploadPdfToAnnouncement(int ID)
    {
        FileManagerController.FileUploadResultDTO files =
            FileManagerController.GetFilesFromRequest((HttpContextWrapper)HttpContext);
        if (String.IsNullOrEmpty(files.ErrorMessage) && files.TotalBytes > 0)
        {
            // add SINGLE file to the announcement
            try
            {
                this._svc.AddAnnouncementPdfDoc(
                    this._svc.GetAnnouncementByID(ID),
                    new PdfDoc(files.Files[0]),
                    new User() { UserName = User.Identity.Name });
            }
            catch (ServiceExceptions.KsisServiceException ex)
            {
                // only handle our exceptions
                base.AddErrorMessageLine(ex.Message);
            }
        }

        // redirect back to detail page
        return RedirectToAction("Detail", "Announcements", new { id = ID });
    }

现在您可以看到我将文件对象传递给我的服务,但您可以选择将其添加到会话中并将ID传递回"预览"视图.

最后,这是一个用于将文件呈现给客户端的通用操作(您可以使用类似的方式呈现来自Session的文件/流):

    //
    // GET: /FileManager/GetFile/ID
    [OutputCache(Order = 2, Duration = 600, VaryByParam = "ID")]
    public ActionResult GetFile(int ID)
    {
        FileService svc = ObjectFactory.GetInstance<FileService>();

        KsisOnline.Data.File result = svc.GetFileByID(ID);

        return File(result.Data, result.MimeType, result.UploadFileName);
    }

编辑:
我注意到我需要更多样品来解释上述情况 -

对于上面的上传操作,FileUploadResultDTO该类:

    public class FileUploadResultDTO
    {
        public List<File> Files { get; set; }
        public Int32 TotalBytes { get; set; }
        public string ErrorMessage { get; set; }
    }

而GetFilesFromRequest功能:

    public static FileUploadResultDTO GetFilesFromRequest(HttpContextWrapper contextWrapper)
    {
        FileUploadResultDTO result = new FileUploadResultDTO();
        result.Files = new List<File>();

        foreach (string file in contextWrapper.Request.Files)
        {
            HttpPostedFileBase hpf = contextWrapper.Request.Files[file] as HttpPostedFileBase;
            if (hpf.ContentLength > 0)
            {
                File tempFile = new File()
                {
                    UploadFileName = Regex.Match(hpf.FileName, @"(/|\\)?(?<fileName>[^(/|\\)]+)$").Groups["fileName"].ToString(),   // to trim off whole path from browsers like IE
                    MimeType = hpf.ContentType,
                    Data = FileService.ReadFully(hpf.InputStream, 0),
                    Length = (int)hpf.InputStream.Length
                };
                result.Files.Add(tempFile);
                result.TotalBytes += tempFile.Length;
            }
        }

        return result;
    }

最后(我希望我现在拥有你需要的一切)这个ReadFully功能.这不是我的设计.我从网上得到它 - 流阅读可能很棘手.我发现这个函数是完全读取流的最成功的方法:

    /// <summary>
    /// Reads data from a stream until the end is reached. The
    /// data is returned as a byte array. An IOException is
    /// thrown if any of the underlying IO calls fail.
    /// </summary>
    /// <param name="stream">The stream to read data from</param>
    /// <param name="initialLength">The initial buffer length</param>
    public static byte[] ReadFully(System.IO.Stream stream, long initialLength)
    {
        // reset pointer just in case
        stream.Seek(0, System.IO.SeekOrigin.Begin);

        // If we've been passed an unhelpful initial length, just
        // use 32K.
        if (initialLength < 1)
        {
            initialLength = 32768;
        }

        byte[] buffer = new byte[initialLength];
        int read = 0;

        int chunk;
        while ((chunk = stream.Read(buffer, read, buffer.Length - read)) > 0)
        {
            read += chunk;

            // If we've reached the end of our buffer, check to see if there's
            // any more information
            if (read == buffer.Length)
            {
                int nextByte = stream.ReadByte();

                // End of stream? If so, we're done
                if (nextByte == -1)
                {
                    return buffer;
                }

                // Nope. Resize the buffer, put in the byte we've just
                // read, and continue
                byte[] newBuffer = new byte[buffer.Length * 2];
                Array.Copy(buffer, newBuffer, buffer.Length);
                newBuffer[read] = (byte)nextByte;
                buffer = newBuffer;
                read++;
            }
        }
        // Buffer is now too big. Shrink it.
        byte[] ret = new byte[read];
        Array.Copy(buffer, ret, read);
        return ret;
    }