Kum*_*thy 5 mysql select insert percentage
我有一个MySQL表,看起来像这样:
Name | Pass | Fail | Pass Percent | Fail Percent
Abdy | 20 | 5 | |
Bob | 10 | 5 | |
Cantona | 40 | 10 | |
Dave | 30 | 20 | |
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我想要获得百分比:
喜欢:passpercent =(传递/传递+失败)*100
我可以用两个列的单个MySQL代码填充表吗?
表有希望看起来像这样:
Name | Pass | Fail | Pass Percent | Fail Percent
Abdy | 20 | 5 | 80 | 20
Bob | 10 | 5 | 66 | 33
Cantona | 40 | 10 | 80 | 20
Dave | 30 | 20 | 60 | 40
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这绝对是可能的.
填写第二个表格:
UPDATE mytable SET pass_pct=(pass/pass+fail)*100,fail_pct=(fail/pass+fail)*100
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当然,您也可以在选择第一个表时生成这些(如果您不想存储结果),例如:
SELECT name,pass,fail,(pass/pass+fail)*100 as pass_pct,(fail/pass+fail)*100 as fail_pct FROM mytable
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