use*_*107 1 html xml xpath xml-parsing
我有以下HTML文档
<div class="books">
<div class="book">
<div>
there are many deep nested elements here, somewhere there will be one span with some text e.g. 'mybooktext' within these
<div>
<div>
<div>
<span>mybooktext</span>
</div>
</div>
</div>
</div>
<div>
there are also many nested elements here, somewhere there will be a link with a class called 'mylinkclass' within these. (this is the element i want to find)
<div>
<div>
<a class="mylinkclass">Bla</a>
</div>
</div>
</div>
</div>
<div class="book">
<div>
there are many deep nested elements here, somewhere there will be one span with some text e.g. 'mybooktext' within these
<div>
<span>mybooktext</span>
</div>
<div>
</div>
<div>
there are also many nested elements here, somewhere there will be a link with a class called 'mylinkclass' within these. (this is the element i want to find)
<div>
<a class="mylinkclass">Bla</a>
</div>
</div>
</div>
<div class="book">
same as above
</div>
</div>
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我想在book元素中找到link元素(链接有名为'mylinkclass'的类),这将基于同一book元素中span的文本.
所以它会是这样的:
- 使用文本'mybooktext'查找范围
-Navigate up book div
- 在book div中找到类'mylinkclass'的链接
这应该使用一个xpath语句完成
在我的几个,这是你正在寻找:
" //span[contains(text(),'mybooktext')]
/ancestor::div[@class='book']
//a[@class='mylinkclass']"
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//span[contains(text(),'mybooktext')]查找包含"mybooktext"的san
/ancestor::div[@class='book']导航书籍div(在任何深层)
//a[@class='mylinkclass']查找书籍div中的类"mylinkclass"的链接(在任何深层)
更新:将第一个条件更改为
//span[(text() ='mybooktext']mybooktext是span中唯一的文本
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