Python PyQt:QTableWidget - 根据标题字符串和选定的行获取单元格值

Question

例如,我有一个PyQt QTableWidget,它有3列和2行.列标题标记为A,B和C.

A B C
1 2 3
4 5 6

这是我目前来源的摘录:

class myform(QtGui.QMainWindow):

    def __init__(self, parent=None):

        super(myform, self).__init__(parent)

        self.ui = Ui_mygui()
        self.ui.setupUi(self)

        self.ui.mytablewidget.cellClicked.connect(self.cell_was_clicked)

    @QtCore.pyqtSlot() # prevents executing following function twice
    def cell_was_clicked(self):
        row = self.ui.mytablewidget.currentItem().row()
        print "row=",row
        col = self.ui.mytablewidget.currentItem().column()
        print "col=",col
        item = self.ui.mytablewidget.horizontalHeaderItem(col).text()
        print "item=",item

我的代码工作,当我在表中选择一行时...我从选择中得到正确的行和列号.

给定指定标题名称,返回所选行的单元格值所需的代码是什么？如果我选择第2行单元格1 ...如何在同一行上获取C列的单元格值？

Answer 1

这是我想出的代码.随意提供反馈.

#===================================================================
# given a tablewidget which has a selected row...
# return the column value in the same row which corresponds to a given column name
# fyi: columnname is case sensitive
#===================================================================

def getsamerowcell(widget,columnname):

    row = widget.currentItem().row()
    #col = widget.currentItem().column()

    #loop through headers and find column number for given column name
    headercount = widget.columnCount()
    for x in range(0,headercount,1):
        headertext = widget.horizontalHeaderItem(x).text()
        if columnname == headertext:
            cell = widget.item(row, x).text()   # get cell at row, col
            return cell