如何在Python中实现看门狗定时器？

Question

我想在Python中实现一个简单的看门狗定时器,有两个用例:

• Watchdog确保函数的执行时间不超过x秒
• 看门狗确保某些经常执行的功能确实执行至少每y秒

我怎么做？

Answer 1

只需发布我自己的解决方案:

from threading import Timer

class Watchdog:
    def __init__(self, timeout, userHandler=None):  # timeout in seconds
        self.timeout = timeout
        self.handler = userHandler if userHandler is not None else self.defaultHandler
        self.timer = Timer(self.timeout, self.handler)
        self.timer.start()

    def reset(self):
        self.timer.cancel()
        self.timer = Timer(self.timeout, self.handler)
        self.timer.start()

    def stop(self):
        self.timer.cancel()

    def defaultHandler(self):
        raise self

用法如果要确保函数在少于x几秒内完成:

watchdog = Watchdog(x)
try:
  # do something that might take too long
except Watchdog:
  # handle watchdog error
watchdog.stop()

用法,如果您经常执行某些操作并希望确保至少每秒执行一次y:

import sys

def myHandler():
  print "Whoa! Watchdog expired. Holy heavens!"
  sys.exit()

watchdog = Watchdog(y, myHandler)

def doSomethingRegularly():
  # make sure you do not return in here or call watchdog.reset() before returning
  watchdog.reset()