我在java中构建了一个文件哈希方法,它接受a的输入字符串表示,filepath+filename然后计算该文件的哈希值.散列可以是任何本机支持的java散列算法,例如MD2through SHA-512.
我试图找出最后一滴性能,因为这个方法是我正在研究的项目的一个组成部分.我被建议尝试使用FileChannel而不是常规FileInputStream.
我原来的方法:
/**
* Gets Hash of file.
*
* @param file String path + filename of file to get hash.
* @param hashAlgo Hash algorithm to use. <br/>
* Supported algorithms are: <br/>
* MD2, MD5 <br/>
* SHA-1 <br/>
* SHA-256, SHA-384, SHA-512
* @return String value of hash. (Variable length dependent on hash algorithm used)
* @throws IOException If file is invalid.
* @throws HashTypeException If no supported or valid hash algorithm was found.
*/
public String getHash(String file, String hashAlgo) throws IOException, HashTypeException {
StringBuffer hexString = null;
try {
MessageDigest md = MessageDigest.getInstance(validateHashType(hashAlgo));
FileInputStream fis = new FileInputStream(file);
byte[] dataBytes = new byte[1024];
int nread = 0;
while ((nread = fis.read(dataBytes)) != -1) {
md.update(dataBytes, 0, nread);
}
fis.close();
byte[] mdbytes = md.digest();
hexString = new StringBuffer();
for (int i = 0; i < mdbytes.length; i++) {
hexString.append(Integer.toHexString((0xFF & mdbytes[i])));
}
return hexString.toString();
} catch (NoSuchAlgorithmException | HashTypeException e) {
throw new HashTypeException("Unsuppored Hash Algorithm.", e);
}
}
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重构方法:
/**
* Gets Hash of file.
*
* @param file String path + filename of file to get hash.
* @param hashAlgo Hash algorithm to use. <br/>
* Supported algorithms are: <br/>
* MD2, MD5 <br/>
* SHA-1 <br/>
* SHA-256, SHA-384, SHA-512
* @return String value of hash. (Variable length dependent on hash algorithm used)
* @throws IOException If file is invalid.
* @throws HashTypeException If no supported or valid hash algorithm was found.
*/
public String getHash(String fileStr, String hashAlgo) throws IOException, HasherException {
File file = new File(fileStr);
MessageDigest md = null;
FileInputStream fis = null;
FileChannel fc = null;
ByteBuffer bbf = null;
StringBuilder hexString = null;
try {
md = MessageDigest.getInstance(hashAlgo);
fis = new FileInputStream(file);
fc = fis.getChannel();
bbf = ByteBuffer.allocate(1024); // allocation in bytes
int bytes;
while ((bytes = fc.read(bbf)) != -1) {
md.update(bbf.array(), 0, bytes);
}
fc.close();
fis.close();
byte[] mdbytes = md.digest();
hexString = new StringBuilder();
for (int i = 0; i < mdbytes.length; i++) {
hexString.append(Integer.toHexString((0xFF & mdbytes[i])));
}
return hexString.toString();
} catch (NoSuchAlgorithmException e) {
throw new HasherException("Unsupported Hash Algorithm.", e);
}
}
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两者都返回正确的哈希值,但重构的方法似乎只对小文件合作.当我传入一个大文件时,它完全窒息而我无法弄清楚原因.我是新手,NIO所以请指教.
编辑:忘了提到我正在通过它投掷SHA-512进行测试.
UPDATE: 使用我现在的方法更新.
/**
* Gets Hash of file.
*
* @param file String path + filename of file to get hash.
* @param hashAlgo Hash algorithm to use. <br/>
* Supported algorithms are: <br/>
* MD2, MD5 <br/>
* SHA-1 <br/>
* SHA-256, SHA-384, SHA-512
* @return String value of hash. (Variable length dependent on hash algorithm used)
* @throws IOException If file is invalid.
* @throws HashTypeException If no supported or valid hash algorithm was found.
*/
public String getHash(String fileStr, String hashAlgo) throws IOException, HasherException {
File file = new File(fileStr);
MessageDigest md = null;
FileInputStream fis = null;
FileChannel fc = null;
ByteBuffer bbf = null;
StringBuilder hexString = null;
try {
md = MessageDigest.getInstance(hashAlgo);
fis = new FileInputStream(file);
fc = fis.getChannel();
bbf = ByteBuffer.allocateDirect(8192); // allocation in bytes - 1024, 2048, 4096, 8192
int b;
b = fc.read(bbf);
while ((b != -1) && (b != 0)) {
bbf.flip();
byte[] bytes = new byte[b];
bbf.get(bytes);
md.update(bytes, 0, b);
bbf.clear();
b = fc.read(bbf);
}
fis.close();
byte[] mdbytes = md.digest();
hexString = new StringBuilder();
for (int i = 0; i < mdbytes.length; i++) {
hexString.append(Integer.toHexString((0xFF & mdbytes[i])));
}
return hexString.toString();
} catch (NoSuchAlgorithmException e) {
throw new HasherException("Unsupported Hash Algorithm.", e);
}
}
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所以我尝试使用我的原始示例和我最新的更新示例,对2.92GB文件的MD5进行基准测试.当然,任何基准测试都是相对的,因为存在操作系统和磁盘缓存以及其他会导致重复读取相同文件的"魔法"......但这里有一些基准测试.我把每个方法加载起来并在将它编译为新鲜后将其关闭5次.基准测试取自最后一次(第5次),因为这将是该算法的"最热门"运行,以及任何"魔术"(在我的理论中无论如何).
Here's the benchmarks so far:
Original Method - 14.987909 (s)
Latest Method - 11.236802 (s)
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这是25.03% decrease用于散列相同的2.92GB文件的时间.非常好.
3条建议:
1)每次读取后清除缓冲区
while (fc.read(bbf) != -1) {
md.update(bbf.array(), 0, bytes);
bbf.clear();
}
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2)不要同时关闭fc和fis,这是多余的,关闭fis就足够了。FileInputStream.close API 说:
If this stream has an associated channel then the channel is closed as well.
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3) 如果你想通过 FileChannel 使用来提高性能
ByteBuffer.allocateDirect(1024);
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