获取链式异常Java的详细消息

Question

我想知道我如何能够选择"最终" Exception,其中包含一条详细信息,其中包含许多链接异常的所有详细信息.

例如,假设这样的代码:

try {
  try {
    try {
      try {
        //Some error here
      } catch (Exception e) {
        throw new Exception("FIRST EXCEPTION", e);
      }
    } catch (Exception e) {
      throw new Exception("SECOND EXCEPTION", e);
    }
  } catch (Exception e) {
    throw new Exception("THIRD EXCEPTION", e);
  }
} catch (Exception e) {
  String allMessages = //all the messages
  throw new Exception(allMessages, e);
}

我对完整不感兴趣stackTrace,但只是在我写的信息中.我的意思是,我想得到这样的结果:

java.lang.Exception: THIRD EXCEPTION + SECOND EXCEPTION + FIRST EXCEPTION

Answer 1

我想你需要的是:

public static List<String> getExceptionMessageChain(Throwable throwable) {
    List<String> result = new ArrayList<String>();
    while (throwable != null) {
        result.add(throwable.getMessage());
        throwable = throwable.getCause();
    }
    return result; //["THIRD EXCEPTION", "SECOND EXCEPTION", "FIRST EXCEPTION"]
}