在Android开发中精确计算,Java？

Question

我正在为Android创建一个计算器,到目前为止它看起来已经完成了......事情是答案不精确,加法,减法,乘法工作正常十进制通常不需要..当涉及到分裂时回答四舍五入到最接近的整数而不是以十进制显示答案...所以我改变了TextView类型以显示小数,并使用float而不是int来表示包含答案的变量.结果是我最终得到一个圆形整数,结尾为".00":/请帮忙!我的代码:MainActivity.java:

package in.rohanbojja.basiccalculator;

import android.app.Activity;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;

public class MainActivity extends Activity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }
    public void add( View view){

        EditText n1 = (EditText) findViewById(R.id.editText1);
        EditText n2 = (EditText) findViewById(R.id.editText3);
        TextView res = (TextView) findViewById(R.id.textView1);

        String sn1 = n1.getText().toString();
        String sn2 = n2.getText().toString();
        String sres;

        int in1 = Integer.parseInt(sn1);
        int in2 = Integer.parseInt(sn2);
        float ires;

        ires = in1 + in2;
        sres = Float.toString(ires);
        res.setText(sres);
}
public void sub( View view ){

    EditText n1 = (EditText) findViewById(R.id.editText1);
    EditText n2 = (EditText) findViewById(R.id.editText3);
    TextView res = (TextView) findViewById(R.id.textView1);

    String sn1 = n1.getText().toString();
    String sn2 = n2.getText().toString();
    String sres;

    int in1 = Integer.parseInt(sn1);
    int in2 = Integer.parseInt(sn2);
    float ires;

    ires = in1 - in2;
    sres = Float.toString(ires);
    res.setText(sres);
}
public void mul( View view ){

    EditText n1 = (EditText) findViewById(R.id.editText1);
    EditText n2 = (EditText) findViewById(R.id.editText3);
    TextView res = (TextView) findViewById(R.id.textView1);

    String sn1 = n1.getText().toString();
    String sn2 = n2.getText().toString();
    String sres;

    int in1 = Integer.parseInt(sn1);
    int in2 = Integer.parseInt(sn2);
    float ires;

    ires = in1 * in2;
    sres = Float.toString(ires);
    res.setText(sres);

}


public void clr( View view ){

    EditText n1 = (EditText) findViewById(R.id.editText1);
    EditText n2 = (EditText) findViewById(R.id.editText3);
    TextView res = (TextView) findViewById(R.id.textView1);

    n1.setText("");
    n2.setText("");
    res.setText("Result");
}

public void div( View view){
    EditText n1 = (EditText) findViewById(R.id.editText1);
    EditText n2 = (EditText) findViewById(R.id.editText3);
    TextView res = (TextView) findViewById(R.id.textView1);

    String sn1 = n1.getText().toString();
    String sn2 = n2.getText().toString();
    String sres;

    int in1 = Integer.parseInt(sn1);
    int in2 = Integer.parseInt(sn2);
    float ires;

    ires = in1/in2;
    sres = Float.toString(ires);
    res.setText(sres);
}
}

Answer 1

int in1 = Integer.parseInt(sn1);
int in2 = Integer.parseInt(sn2);
float ires;

ires = in1/in2;

你仍在进行整数除法,你只是将结果存储在浮点数中.要执行浮点除法,in1和in2必须是浮点数.