使用起始值对对象List进行排序的最佳方法是什么?我的清单中有以下项目:
obj a
obj b
obj c
obj d
a.index = 1
b.index = 3
c.index = 2
d.index = 4
start value = 3;
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排序列表必须是 {b,d,a,c}
感谢帮助.
使用OrderBy和ThenBy组合.它将using System.Linq在您的文件顶部工作.
var source = new List<Item>() {
new Item { index = 1, value = 'a' },
new Item { index = 3, value = 'b' },
new Item { index = 2, value = 'c' },
new Item { index = 4, value = 'd' },
};
int startValue = 3;
var sortedList = source.OrderBy(i => i.index < startValue)
.ThenBy(i => i.index)
.ToList();
foreach (var item in sortedList)
Console.WriteLine(string.Format("{0} - {1}", item.value, item.index));
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Item 类定义:
class Item
{
public char value { get; set; }
public int index { get; set; }
}
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返回所需的输出:
b - 3
d - 4
a - 1
c - 2
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