根据拆分排序列表

Question

我有一个List很长的时间Strings:

test:test:test:test:test:test:test:ABC:test:test:test:test:test:test:  
test:test:test:test:test:test:test:DEF:test:test:test:test:test:test:  
test:test:test:test:test:test:test:GHI:test:test:test:test:test:test:  
test:test:test:test:test:test:test:JKL:test:test:test:test:test:test:  
test:test:test:test:test:test:test:MNO:test:test:test:test:test:test:  

假设所有测试彼此不同.我想根据大写字母所在的特定位置对这些字符串进行排序.

    for (int i = 0; i < aList.size(); i++) {
        System.out.println(list.get(i).toString().split(":")[7]);
    }

Answer 1

使用Collections.sort()并提供自定义Comparator以强制执行所需的订购标准.

这是一个例子(检查空值和遗漏的意外格式):

List<String> myList;
Collections.sort(myList, new Comparator<String>(){
    @Override
    public int compare(String o1, String o2) {
        String text1 = o1.split(":")[7];
        String text2 = o2.split(":")[7];
        return text1.compareTo(text2);
    }
});