文本字段的Javascript电话面具与正则表达式

Question

我正在使用这个功能来电话面具,几乎完美的工作.

function mask(o, f) 
{ 
    v_obj = o; 
    v_fun = f; 
    setTimeout("execmask()", 1) 
};

function execmask() 
{ 
    v_obj.value = v_fun(v_obj.value) 
};

function mphone(v){
    v=v.replace(/\D/g,"");           
    v=v.substring(0, 11);
    v=v.replace(/^(\d{2})(\d)/g,"(OXX$1) $2"); 
    v=v.replace(/(\d)(\d{4})$/,"$1-$2"); 
    return v;
}

在这里,我在文本字段中运行蒙版:

<input type="text" id="phone" name="phone" onkeypress="mask(this, mphone);" onblur="mask(this, mphone);" />

问题是我需要更改代码的这部分(OXX $ 1)为(0XX $ 1).

9位数的现状:(OXX99)99999-9999.

8位数的现状:(OXX99)9999-9999.

我需要9位数的正确格式:(0XX99)99999-9999

我需要8位数的正确格式:(0XX99)99999-9999

8或9位的数量是用户的选择.

如果我将字符'O'更改为'0',则会导致掩码出错.

请帮忙!

Answer 1

function mask(o, f) {
    setTimeout(function () {
        var v = f(o.value);
        if (v != o.value) {
            o.value = v;
        }
    }, 1);
}

function mphone(v) {
    var r = v.replace(/\D/g,"");
    r = r.replace(/^0/,"");
    if (r.length > 10) {
        // 11+ digits. Format as 5+4.
        r = r.replace(/^(\d\d)(\d{5})(\d{4}).*/,"(0XX$1) $2-$3");
    }
    else if (r.length > 5) {
        // 6..10 digits. Format as 4+4
        r = r.replace(/^(\d\d)(\d{4})(\d{0,4}).*/,"(0XX$1) $2-$3");
    }
    else if (r.length > 2) {
        // 3..5 digits. Add (0XX..)
        r = r.replace(/^(\d\d)(\d{0,5})/,"(0XX$1) $2");
    }
    else {
        // 0..2 digits. Just add (0XX
        r = r.replace(/^(\d*)/, "(0XX$1");
    }
    return r;
}

http://jsfiddle.net/BBeWN/