shell脚本中的递归问题

Question

function syncfile(){
                echo "[ DONE $file ]"
        return ;
}
function syncfolder(){

        folder=$1
        for foo in `ls -1 $folder`
        do

                file="$folder/$foo"

                        if [ -d $file ];then
                                syncfolder $file
                        elif [ -e $file ];then
                                syncfile $file
                        else
                                echo "$file is neither file nor directory"
                        fi
        done
        return;
}

上面是我的两个递归函数..当我调用syncfolder $foldername它时, 在下面的情况下没有给出正确的输出..

假设层次结构如下所示

portchanges/
portchanges/script/script1/script1.sh
portchanges/script/script1/script2.sh
portchanges/script/script1/script3.sh

portchanges/script/script4.sh
portchanges/script/script5.sh

portchanges/script6.sh
portchanges/script7.sh

portchanges/appl/script11/script11.sh
portchanges/appl/script11/script12.sh
portchanges/appl/script11/script13.sh

现在如果foldername=portchanges 和我打电话syncfolder $foldername

它仅用于处理

portchanges/script/script1/script1.sh
portchanges/script/script1/script2.sh
portchanges/script/script1/script3.sh

与function syncfile()函数调用...然后它去return的syncfolder功能.

它会搜索script6.sh并script7.sh在portchanges/script/script1/目录!这是完全不正当的行为!!

我应该怎么做syncfile()呢？它会递归处理整个文件夹,并且每个文件都能正常运行？

Answer 1

将folder变量声明为local.您不希望递归调用更改调用方变量的值.