如何按顺序制作junit测试运行方法

Question

伙计们!我有一个新问题.我正在使用不同的缓存管理器向缓存添加一些数据,我正面临着它的问题.我是用junit和spring做的.当我运行测试时,测试方法是随机执行的,但我需要按顺序执行它们.怎么做？？这是一些代码和证明控制台输出:

服务类:

@Service("HelloCache")
public class CacheServiceImpl implements CacheInterface {
    @Autowired
    @Qualifier("memcachedClient")
    private MemcachedClient mBean;

    public void Add(String key, Object object) {
        mBean.set(key, 12, object);
    }

    public void Get(String key) {
        mBean.get(key);
    }

    public void Delete(String key) {
        mBean.delete(key);
    }    
}

这是测试:

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = "file:src/main/java/spring.xml")
public class UsingMemcachedTest extends TestCase {
    @Autowired
    @Qualifier("HelloCache")
    private CacheInterface emcached;
    private byte[][] i = new byte[2500][3000];
    private String key = "j";
    @Test
    public void testAddBulkObjects() {
        System.out.println("");
        System.out.println("This is async BULK adding test");
        long time = System.currentTimeMillis();
        for (int k=1; k<=1000; k++) {
            emcached.Add(key+k, i);
        }
        long time2 = System.currentTimeMillis();
        long timeE=time2-time;
        System.out.println("Vremya add BULK objects: " + timeE);
        System.out.println("");
    }

    @Test
    public void testGetBulkObjects() {
        System.out.println("");
        System.out.println("This is getting BULK objects test");
        long time = System.currentTimeMillis(); 
        for (int k=1; k<=1000; k++) {
            emcached.Get(key+k);
        }
        long time2 = System.currentTimeMillis();
        long timeE=time2-time;
        System.out.println("Vremya Get object: " + timeE);
        System.out.println("");
    } 

    @Test
    public void testDeleteBulkObjects() {
        System.out.println("");
        System.out.println("This is deleting BULK objects test");
        long time = System.currentTimeMillis();
        for (int k=1; k<=1000; k++) {
            emcached.Delete(key+k);
        }
        long time2 = System.currentTimeMillis();
        long timeE=time2-time;
        System.out.println("Vremya delete object: " + timeE);
        System.out.println("");
    }

并输出:

This is deleting BULK objects test
Vremya delete object: 137


This is getting BULK objects test
Vremya Get object: 703


This is async BULK adding test
Vremya add BULK objects: 87681

请帮忙!!=)

Answer 1

从版本4.11开始,您可以使用注释指定执行顺序,并按方法名称排序:

import org.junit.Test;
import org.junit.FixMethodOrder;
import org.junit.runners.MethodSorters;

@FixMethodOrder(MethodSorters.NAME_ASCENDING)
public class MyTest {

    @Test
    public void test1Create() {
        System.out.println("first");
    }

    @Test
    public void test2Update() {
        System.out.println("second");
    }
}

请参阅JUnit 4.11发行说明

Answer 2

JUnit对您的测试运行顺序没有任何承诺.顺序将根据运行测试的环境和上下文而有所不同.

出于这个原因(和其他人),对于影响测试行为的排序,它被认为是非常糟糕的测试设计.您可以使用@Before为您提供一个干净的平板,然后在特定测试中进行任何设置作为该测试的一部分.

以下问题的接受答案给出了一个很好的解释并链接到一些有用的资源: 如何在JUnit4中按特定顺序运行测试方法？