使用变量作为表名的mysql错误

Han*_*nny 5 mysql sql select

为什么我收到此错误?

CREATE DEFINER=`root`@`localhost` PROCEDURE `selectrecords`(tablename varchar(50))
begin
set @table_name=tablename;
set @sql_text=concat('Select * from @table_name');
prepare statement from @sql_text;
execute statement;
deallocate prepare statement;
end
Run Code Online (Sandbox Code Playgroud)

错误:

....to use near '@table_name' at line 1
Run Code Online (Sandbox Code Playgroud)

我的代码是正确的,但我不明白为什么....

Joh*_*Woo 4

我想你的意思是

CREATE PROCEDURE `selectrecords`(tablename varchar(50))
begin
    set @sql_text = concat('Select * from ', tablename);
    prepare statement from @sql_text;
    execute statement;
    deallocate prepare statement;
end
Run Code Online (Sandbox Code Playgroud)

即使在动态SQL 中,您也无法参数化表名和列名,因此您唯一的选择就是与字符串连接。占位符中只能放置值。


更新1

CREATE PROCEDURE `selectrecords`(tablename varchar(50))
begin
    set @val = idnumber;
    set @sql_text = concat('Select * from ', tablename, ' WHERE id = ?');
    prepare statement from @sql_text;
    execute statement USING @val;
    deallocate prepare statement;
end
Run Code Online (Sandbox Code Playgroud)