我目前正在haskell中制作基于文本的菜单系统.我创建了一个名为Book的数据类型,其中每个函数都编辑列表并返回它.但是,我无法弄清楚如何使菜单部分工作,它可以编辑此列表并回过头来.
关于我在菜单上工作的例子,将一本书添加到列表中,然后菜单需要重新加载菜单以便我可以使用新添加的书籍来显示.
菜单的例子
menu:: [Book] -> [IO]
menu books = do
str <- getLine
let selectNum = (read str :: Int)
case selectNum of
1 -> let sd = addNewBookIO books
2 -> displayAllBooksFromYear books
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添加新书的示例
addNewBookIO :: [Book] -> IO [Book]
addNewBookIO films =
do putStr "Film name: "
filmTitle <- getLine
putStr "List all cahr in the Book (separated by commas): "
cast <- addToStringArray []
putStr "Year of Realese in the UK: "
year <- getLine
let test = (read year :: Int)
putStr "List all the fans(separated by commas): "
fans <- addToStringArray []
putStrLn "Your Book has been added"
let bookList = addbookFilm (Film bookTitle cast test fans) films
return bookList
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任何帮助将不胜感激
目前你的类型签名menu没有任何意义.你的意思是这样的吗?
menu :: [Book] -> IO [Book]
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如果是这样,那么你可以定义它
menu books = do
str <- getLine
case read str of
1 -> do books' <- addNewBookIO books -- add a new book, then loop
menu books'
2 -> displayAllBooksFromYear books >> menu books -- display books, then loop
3 -> return books -- quit
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这将从用户读取一个字符串,然后添加一本新书,显示当前的书籍列表或结束循环,返回书籍列表.
编辑:该>>算子的两个操作在一起.组合a >> b意味着"做a,然后做b".
以下两段代码完全等效(实际上,第一段代码只是第二段的语法糖)
do displayAllBooksFromYear books
menu books
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和
displayAllBooksFromYear books >> menu books
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希望有助于澄清事情.