Socket.io广播到没有在socket.io v.0.9.13中工作的房间

Question

socket.broadcast.to(newroom).emit('updatechat', 'SERVER', socket.username+' has joined this room');

没有打到客户端.我只能看到来自的消息:

socket.emit('updateActivity', 'SERVER', 'you have CONNECTED to '+ socketEntity.roomName);

我做错了socket.join()什么？

我也试图给广播事件一个不同的名字而不是updateActivity,但它也不会起作用.

在日志输出中没有提到有关广播发射的信息.

问题更新:

我找到了一个解决方案,如果我将broadcast.to()替换为以下代码段,它将起作用:

socket.get(socketEntity.roomId, function (error, room) {
   io.sockets.in(room).emit('updateActivity', 'SERVER', 'you -joined- this group '+ socketEntity.roomName);
});

但是我不知道为什么会出现这种情况......所以roomio.sockets.in()的参数在某种程度上isn't与字符串相同socketEntity.roomId？

原始代码:

服务器:

io.sockets.on ('connection', function (socket){
    socket.on('joinRoom', function(socketEntity){
        socket.join(socketEntity.roomId);
        socket.emit('updateActivity', 'SERVER', 'you have CONNECTED to '+ socketEntity.roomName);
        socket.broadcast.to(socketEntity.roomId).emit('updateActivity', 'SERVER', 'you -joined- this room'+ socketEntity.roomName);
    });
});

客户:

HTML:

<ul id="activityList" class="dropdown-menu"></ul>

JavaScript的:

$(document).ready(function(){
    var socketEntity = {roomId:sampleRmId, roomName: "sample room"}
    socket.emit('joinRoom', socketEntity);


    socket.on('updateActivity', function (username, data){
        $('#activityList').prepend('<li><a href="#"><div>'+ data +'</div></a></li>');
    });
})

Answer 1

socket.broadcast 将消息发送给除被调用的客户端之外的所有其他客户端.

socket.emit 仅发送给该特定客户端

io.sockets.emit 发送给所有客户