And*_*uri 0 c++ floating-point precision matlab
我正在用c ++创建一个用于计算机视觉的庞大程序,为了调试目的,我使用Matlab.经过一段时间的战斗,我意识到使用Matlab和c ++(Visual Studio 9编译器BTW)时,一些简单的算术方程的答案是不同的.这是为什么?
这是算术运算:
Matlab功能:
function [x,y]=shape_fun(p,shape,Ax,Ay)
x=p(1)+Ax+shape(1)+Ax.*shape(3)+Ay.*shape(4)+Ax.*Ax.*shape(5)/2+Ay.*Ay.*shape(6)/2+Ax.*Ay.*shape(7);
y=p(2)+Ay+shape(2)+Ax.*shape(8)+Ay.*shape(9)+Ax.*Ax.*shape(10)/2+Ay.*Ay.*shape(11)/2+Ax.*Ay.*shape(12);
end
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C++函数
cv::Point2d deformed(const double shape_fun[12],const cv::Point2d p,const double Ax,const double Ay){
cv::Point2d result;
result.x=(p.x+Ax)+shape_fun[0]+shape_fun[2]*Ax+shape_fun[3]*Ay+shape_fun[4]*Ax*Ax/2*shape_fun[5]*Ay*Ay/2+shape_fun[6]*Ax*Ay;
result.y=(p.y+Ay)+shape_fun[1]+shape_fun[7]*Ax+shape_fun[8]*Ay+shape_fun[9]*Ax*Ax/2*shape_fun[10]*Ay*Ay/2+shape_fun[11]*Ax*Ay;
return result;
}
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数据:
注意:Matlab值是从debbuger c ++值复制粘贴的,它们完全相同.
Ax=-12
Ay=-12
p=[468,683];
shape=[
63.178114688537441
36.536135487588474
-0.038695673779030673
-0.045313362559036965
0.016469896824803026
0.0017122284868442948
-0.0030285669997117204
-0.067902655024060773
0.17995980761526389
0.012716871878336870
-0.036890386929202310
-0.00081243692842574420
];
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结果:
Matlab:
x =
3.947029931219995e+02
y =
7.043339656551383e+02
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C++:
result {x=393.54007007383439 y=703.64248713855773 } cv::Point_<double>
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注意:我没有OpenCV故意标记问题.虽然显然我OpenCV在C++中使用,但cv::Point2d它只是一个带有两个double变量x和y的结构,我不认为这个问题是关于它OpenCV的.
joh*_*ohn 10
result.x=
(p.x+Ax)+
shape_fun[0]+
shape_fun[2]*Ax+
shape_fun[3]*Ay+
shape_fun[4]*Ax*Ax/2*
shape_fun[5]*Ay*Ay/2+
shape_fun[6]*Ax*Ay;
result.y=
(p.y+Ay)+
shape_fun[1]+
shape_fun[7]*Ax+
shape_fun[8]*Ay+
shape_fun[9]*Ax*Ax/2*
shape_fun[10]*Ay*Ay/2+
shape_fun[11]*Ax*Ay;
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应该(推测)
result.x=
(p.x+Ax)+
shape_fun[0]+
shape_fun[2]*Ax+
shape_fun[3]*Ay+
shape_fun[4]*Ax*Ax/2+ /** change here **/
shape_fun[5]*Ay*Ay/2+
shape_fun[6]*Ax*Ay;
result.y=
(p.y+Ay)+
shape_fun[1]+
shape_fun[7]*Ax+
shape_fun[8]*Ay+
shape_fun[9]*Ax*Ax/2+ /** change here **/
shape_fun[10]*Ay*Ay/2+
shape_fun[11]*Ax*Ay;
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