类比Python的默认值？

Question

是否有Python的.NET模拟defaultdict？我发现编写短代码很有用,例如.计数频率:

>>> words = "to be or not to be".split()
>>> print words
['to', 'be', 'or', 'not', 'to', 'be']
>>> from collections import defaultdict
>>> frequencies = defaultdict(int)
>>> for word in words:
...     frequencies[word] += 1
... 
>>> print frequencies
defaultdict(<type 'int'>, {'not': 1, 'to': 2, 'or': 1, 'be': 2})

理想情况下,在C#中,我可以写:

var frequencies = new DefaultDictionary<string,int>(() => 0);
foreach(string word in words)
{
    frequencies[word] += 1
}

Answer 1

一些可以让你开始的东西。我基本上只是改变了this索引器。由于我不知道 python 的完整功能，defaultdict我无法进一步改进它。你给出的例子会起作用。

public class DefaultDictionary<TKey, TValue> : IDictionary<TKey,TValue>
{
    private readonly Func<TValue> _defaultSelector;
    private readonly Dictionary<TKey, TValue> _values = new Dictionary<TKey, TValue>();

    public DefaultDictionary()
        : this(() => default(TValue))
    {
    }

    public DefaultDictionary(Func<TValue> defaultSelector)
    {
        _defaultSelector = defaultSelector;
    }

    public IEnumerator<KeyValuePair<TKey, TValue>> GetEnumerator()
    {
        return _values.GetEnumerator();
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }

    public void Add(KeyValuePair<TKey, TValue> item)
    {
        ((IDictionary<TKey,TValue>)_values).Add(item);
    }

    public void Clear()
    {
        _values.Clear();
    }

    public bool Contains(KeyValuePair<TKey, TValue> item)
    {
        return ((IDictionary<TKey,TValue>)_values).Contains(item);
    }

    public void CopyTo(KeyValuePair<TKey, TValue>[] array, int arrayIndex)
    {
        ((IDictionary<TKey, TValue>)_values).CopyTo(array, arrayIndex);
    }

    public bool Remove(KeyValuePair<TKey, TValue> item)
    {
        return ((IDictionary<TKey, TValue>)_values).Remove(item);
    }

    public int Count { get { return _values.Count; } }
    public bool IsReadOnly { get { return ((IDictionary<TKey, TValue>) _values).IsReadOnly; } }
    public bool ContainsKey(TKey key)
    {
        return _values.ContainsKey(key);
    }

    public void Add(TKey key, TValue value)
    {
        _values.Add(key, value);
    }

    public bool Remove(TKey key)
    {
        return _values.Remove(key);
    }

    public bool TryGetValue(TKey key, out TValue value)
    {
        return _values.TryGetValue(key, out value);
    }

    public TValue this[TKey key]
    {
        get
        {
            if (!_values.ContainsKey(key))
            {
                _values.Add(key, _defaultSelector());
            }
            return _values[key];
        }
        set
        {
            if(!_values.ContainsKey(key))
            {
                _values.Add(key, _defaultSelector());
            }
            _values[key] = value;
        }
    }

    public ICollection<TKey> Keys { get { return _values.Keys; } }
    public ICollection<TValue> Values { get { return _values.Values; } }

    public Dictionary<TKey, TValue> ToDictionary()
    {
        return new Dictionary<TKey, TValue>(_values);
    }
}

Answer 2

这是一个简单的实现：

public class DefaultDictionary<TKey, TValue> : Dictionary<TKey, TValue> where TValue : new()
{
    public new TValue this[TKey key]
    {
        get
        {
            TValue val;
            if (!TryGetValue(key, out val))
            {
                val = new TValue();
                Add(key, val);
            }
            return val;
        }
        set { base[key] = value; }
    }
}

以及如何使用它：

var dict = new DefaultDictionary<string, int>();
Debug.WriteLine(dict["foo"]);  // prints "0"
dict["bar"] = 5;
Debug.WriteLine(dict["bar"]);  // prints "5"

或像这样：

var dict = new DefaultDictionary<string, List<int>>();
dict["foo"].Add(1);
dict["foo"].Add(2);
dict["foo"].Add(3);

Answer 3

我认为没有等效的，但根据您的示例，您可以使用 LINQ 执行此操作：

var words = new List<string>{ "One", "Two", "Three", "One" };
var frequencies = words.GroupBy (w => w).ToDictionary (w => w.Key, w => w.Count());