我有2个列表:其中1个是列表列表.他们如下─
lists_of_lists = ['1', '4', '7', '13', '16', '21', '32', '36'],['3', '6', '8', '14', '22', '26', '31', '40']
just_a_list =['THEQUICKBROWNFOXJUMPEDOVERTHELAZYDOG', 'IWOULDLOVETOGETOVERWITHTHISASSOONASPOSSIBLE']
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lists_of_lists用于对just_a_list的元素进行切片,以便:
['1', '4', '7', '13', '16', '21', '32', '36']将对字符串进行切片'THEQUICKBROWNFOXJUMPEDOVERTHELAZYDOG',如下所示
'1' - '4' - 'HEQU'
'7' - '13' - 'KBROWNF'
'16' - '21' - 'JUMPED'
'32' - '36' - 'ZYDOG'
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要点 -
每个列表中
list_of_lists都有偶数个数字.
i'th位置中的列表list_of_lists将属于位于其中的i'th位置的字符串just_a_list.
请帮助我如何执行上述过程..
谢谢
使用zip()字符串和切片名单组合,然后用zip()加iter()招配对的启动和停止值:
for slicelist, text in zip(lists_of_lists, just_a_list):
for start, stop in zip(*([iter(slicelist)]*2)):
print(text[int(start):int(stop) + 1])
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请注意,我们必须在停止索引中添加 1,因为您似乎需要包含它,而在Python中,停止索引是独占的.
这给出了:
>>> for slicelist, text in zip(lists_of_lists, just_a_list):
... for start, stop in zip(*([iter(slicelist)]*2)):
... print(text[int(start):int(stop) + 1])
...
HEQU
KBROWNF
JUMPED
YDOG
ULDL
VETOGET
HTHIS
ONASPOSSIB
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