为什么 python 字典中的字符串键的写入/读取速度比元组慢?

Tho*_*mas 2 python dictionary key

在尝试优化模仿树结构的程序的速度时(“树”存储在以笛卡尔坐标 x,y 坐标对作为键的 DICT 中),我发现将它们的唯一地址作为元组存储在字典中,而不是与字符串相比,运行时间要快得多。

我的问题是,如果 Python 针对字典和哈希中的字符串键进行了优化,为什么在这个示例中使用元组会快得多?在执行完全相同的任务时,字符串键似乎要花费 60% 的时间。我在我的例子中忽略了一些简单的事情吗?

我引用这个线程作为我的问题的基础(以及其他同样断言字符串更快的线程):使用字符串作为字典中的键总是更快吗?

下面是我用来测试这些方法并计时的代码:

import time

def writeTuples():
    k = {}
    for x in range(0,500):
        for y in range(0,x):
            k[(x,y)] = "%s,%s"%(x,y)
    return k

def readTuples(k):
    failures = 0
    for x in range(0,500):
        for y in range(0,x):
            if k.get((x,y)) is not None: pass
            else: failures += 1
    return failures

def writeStrings():
    k = {}
    for x in range(0,500):
        for y in range(0,x):
            k["%s,%s"%(x,y)] = "%s,%s"%(x,y)
    return k

def readStrings(k):
    failures = 0
    for x in range(0,500):
        for y in range(0,x):
            if k.get("%s,%s"%(x,y)) is not None: pass
            else: failures += 1
    return failures

def calcTuples():
    clockTimesWrite = []
    clockTimesRead = []
    failCounter = 0
    trials = 100

    st = time.clock()
    for x in range(0,trials):
        startLoop = time.clock()
        k = writeTuples()
        writeTime = time.clock()
        failCounter += readTuples(k)
        readTime = time.clock()
        clockTimesWrite.append(writeTime-startLoop)
        clockTimesRead.append(readTime-writeTime)

    et = time.clock()

    print("The average time to loop with tuple keys is %f, and had %i total failed records"%((et-st)/trials,failCounter))
    print("The average write time is %f, and average read time is %f"%(sum(clockTimesWrite)/trials,sum(clockTimesRead)/trials))
    return None

def calcStrings():
    clockTimesWrite = []
    clockTimesRead = []
    failCounter = 0
    trials = 100

    st = time.clock()
    for x in range(0,trials):
        startLoop = time.clock()
        k = writeStrings()
        writeTime = time.clock()
        failCounter += readStrings(k)
        readTime = time.clock()
        clockTimesWrite.append(writeTime-startLoop)
        clockTimesRead.append(readTime-writeTime)

    et = time.clock()
    print("The average time to loop with string keys is %f, and had %i total failed records"%((et-st)/trials,failCounter))
    print("The average write time is %f, and average read time is %f"%(sum(clockTimesWrite)/trials,sum(clockTimesRead)/trials))
    return None

calcTuples()
calcStrings()
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谢谢!

Sea*_*ira 5

测试的权重不公平(因此存在时间差异)。format您在循环中对writeStrings循环的调用次数是循环中的两倍writeTuples,并且在 中对它的调用次数是无限多的readStrings。为了进行更公平的测试,您需要确保:

  • %两个写循环仅对每个内部循环进行一次调用
  • readStrings两者readTuples都对每个内部循环进行一次或零次调用%