现在我有一个应用程序搜索并返回ListFragment中的项目.我希望能够使每个ListFragment可单击,这样当单击它时,新活动将开始使用以下内容:
public void onListItemClick(ListView listView, View view, int position, long id) {
Intent i = new Intent(this, PlaceView.class);
startActivity(i);
//eventually data from the List will be passed to the new Activity...
}
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启动我需要点击的ListFragment的类如下:
public class ResultsView extends FragmentActivity {
private ArrayAdapter<String> mAdapter;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_results_view);
//Receive searchTerm from MainActivity
Intent intent = getIntent();
String searchTerm = intent.getStringExtra(MainActivity.SEARCH_TERM);
mAdapter = new ArrayAdapter<String>(this, R.layout.item_label_list);
FragmentManager fm = getSupportFragmentManager();
FragmentTransaction ft = fm.beginTransaction();
ListFragment list = new ListFragment();
ft.add(R.id.fragment_content, list);
// Let's set our list adapter to a simple ArrayAdapter.
list.setListAdapter(mAdapter);
FactualResponderFragment responder = (FactualResponderFragment) fm.findFragmentByTag("RESTResponder");
if (responder == null) {
responder = new FactualResponderFragment();
ft.add(responder, "RESTResponder");
}
Bundle bundle = new Bundle();
bundle.putString("search_term", searchTerm);
responder.setArguments(bundle);
ft.commit();
}
public ArrayAdapter<String> getArrayAdapter() {
return mAdapter;
}
public void onListItemClick(ListView listView, View view, int position, long id) {
Intent i = new Intent(this, PlaceView.class);
startActivity(i);
}
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所以我的问题是:
1)如何设置onListItemClick()与ListFragment list我合作的工作?
2)ListView没有任何与之相关的XML属性onClick.这没关系吗?
3)在哪里onListItemClick(),onItemClickListener()以及其他适用的是什么?
谢谢你的帮助.
编辑:
按照Pramod的建议,我做了一个课程:ListFragmentClickable extends ListFragment并用以下内容填充:
@Override
public void onListItemClick(ListView listView, View view, int position, long id) {
Intent i = new Intent(this, PlaceView.class);
startActivity(i);
}
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Eclipse告诉我这new Intent(this, PlaceView.class)是不允许的,我只能说Intent i = new Intent();.错误是"构造函数Intent(ListFragmentClickable,Class)未定义." 我试图实例化作为意向Eclipse的建议,然后加入i.setClass(this, PlaceView.class)和i.setClassName(this, PlaceView.class),但没有奏效,因为我得到了同样的错误.
1)如何解决此错误并按计划覆盖该方法?
2)如果我不能这样做,并且必须使用Intent i = new Intent();,我该如何判断我们甚至瞄准的课程?
小智 7
试试吧,
Intent intent = new Intent(getActivity().getApplicationContext(), YourClassName.class);
startActivity(Intent intent);
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其中"YourClassName"是您要调用的类的类型.
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