Can*_*lms 0 java switch-statement
当我通过一个简单的Enum测试器迭代for-each循环和switch语句来输出枚举值时,我看到的行为对我来说似乎很奇怪.
码:
public class EnumTest {
private Number number;
public EnumTest(Number number) {
this.number = number;
}
public enum Number {
ONE,
TWO,
THREE,
FOUR,
FIVE;
}
private void tellItLikeItIs() {
switch (number) {
case ONE:
System.out.println("ONE");
case TWO:
System.out.println("TWO");
case THREE:
System.out.println("THREE");
case FOUR:
System.out.println("FOUR");
case FIVE:
System.out.println("FIVE");
}
}
public static void main(String[] args) {
for (Number n : Number.values()) {
EnumTest et = new EnumTest(n);
et.tellItLikeItIs();
System.out.println();
}
}
}
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输出:
ONE
TWO
THREE
FOUR
FIVE
TWO
THREE
FOUR
FIVE
THREE
FOUR
FIVE
FOUR
FIVE
FIVE
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为什么每个调用都会返回自身以及所有后续值?
那是因为你忘记了break;
陈述......
private void tellItLikeItIs() {
switch (number) {
case ONE:
System.out.println("ONE");
break;
case TWO:
System.out.println("TWO");
break;
case THREE:
System.out.println("THREE");
break;
case FOUR:
System.out.println("FOUR");
break;
case FIVE:
System.out.println("FIVE");
break;
}
}
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在这里阅读有关switch语句的更多信息:
如果没有它们,switch块中的语句将会失败:匹配的case标签之后的所有语句将按顺序执行,而不管后续case标签的表达式如何,直到遇到break语句为止