假设输入矩阵是A,这应该是诀窍:
find(A==min(A) & A<0)
Run Code Online (Sandbox Code Playgroud)
例如:
>> A = [1, 2, 3, 4];
>> B = [1, 4, -7, -2];
>> find(A==min(A) & A<0)
ans =
Empty matrix: 1-by-0
>> find(B==min(B) & B<0)
ans =
3
Run Code Online (Sandbox Code Playgroud)