从pycurl返回的字典中提取数据

Question

我有这个:

import pycurl
import pprint
import json

c = pycurl.Curl()
c.setopt(c.URL, 'https://mydomainname.com')

c.perform()

上面的代码返回一个这样的字典:

{"name":"steve", "lastvisit":"10-02-2012", "age":12}

我想循环通过该字典并获得年龄:

age : 12

我试过了:

diction = {}
diction = c.perform()
pprint.pprint(diction["age"])

没有数据返回,我收到此错误:

TypeError: 'NoneType' object is unsubscriptable

Answer 1

c.perform()不返回任何内容,您需要配置类似文件的对象来捕获值.一个BytesIO对象可以做,然后你可以.getvalue()在调用完成后调用它:

import pycurl
import pprint
import json
from io import BytesIO

c = pycurl.Curl()
data = BytesIO()

c.setopt(c.URL, 'https://mydomainname.com')
c.setopt(c.WRITEFUNCTION, data.write)
c.perform()

dictionary = json.loads(data.getvalue())
pprint.pprint(dictionary["age"])

如果你没有结婚pycurl,你可能会发现requests更容易:

import pprint
import requests

dictionary = requests.get('https://mydomainname.com').json()
pprint.pprint(dictionary["age"])

甚至标准库urllib.request模块也比使用更容易pycurl:

from urllib.request import urlopen
import pprint
import json

response = urlopen('https://mydomainname.com')
dictionary = json.load(response)
pprint.pprint(dictionary["age"])