如何在sql select中排除具有特定值的记录

Question

我如何只选择没有客户端的商店5？

StoreId   ClientId   
-------   ---------
  1         4     
  1         5      
  2         5     
  2         6      
  2         7   
  3         8

我正在尝试这样的事情:

SELECT SC.StoreId FROM StoreClients
INNER JOIN StoreClients SC
    ON StoreClients.StoreId = SC.StoreId
    WHERE SC.ClientId = 5
GROUP BY StoreClients.StoreId

这似乎让我的一切,有客户门店,但我不能这样做,因为如果我做相反的<> 5病仍然获得商店1和2我不想要的.

我基本上试图在另一个查询的EXISTS IN子句中使用此结果

Answer 1

单程:

SELECT DISTINCT sc.StoreId
FROM StoreClients sc
WHERE NOT EXISTS(
    SELECT * FROM StoreClients sc2 
    WHERE sc2.StoreId = sc.StoreId AND sc2.ClientId = 5)

Answer 2

SELECT SC.StoreId 
FROM StoreClients SC
WHERE SC.StoreId NOT IN (SELECT StoreId FROM StoreClients WHERE ClientId = 5)

这样既不是JOIN也GROUP BY不必要.

Answer 3

SELECT  DISTINCT a.StoreID
FROM    tableName a
        LEFT JOIN tableName b 
          ON a.StoreID = b.StoreID AND b.ClientID = 5
WHERE   b.StoreID IS NULL

• SQLFiddle演示

OUTPUT

???????????
? STOREID ?
???????????
?       3 ?
???????????

Answer 4

SELECT StoreId
FROM StoreClients
WHERE StoreId NOT IN (
  SELECT StoreId
  FROM StoreClients
  Where ClientId=5
)

SQL小提琴