C++排序矢量字符串不起作用

Emr*_*s90 2 c++ string compare vector

由于某种原因,我不能正确地得到这种名称.谁能告诉我它有什么问题?据我所知,问题是字符串没有正确比较.我以前尝试过字符串比较,我知道这种代码应该可行.真的让我难过.

#include <iostream>
#include <fstream>
#include <string>
#include <vector>

using namespace std;

void sortNames(vector<string> &);

void main()
{
    vector<string> namesList;
    ifstream namesFile;
    namesFile.open("Names.txt");

    // Make sure the file exists.
    if (namesFile)
    {
        // Get the names from the file.
        string name;
        while (getline(namesFile, name))
            namesList.push_back(name);

        // Sort the imported names.
        sortNames(namesList);

        for (int i = 0; i < namesList.size(); i++)
            cout << namesList[i] << endl;
    }
    else
    {
        cout << "Data files are missing";
    }

    namesFile.close();
}

void sortNames(vector<string> &list)
{
    for (int i = 0; i < list.size(); i++)
    {
        // Find the lowest value after i.
        int lowIndex = i;
        for (int j = i + 1; j < list.size(); j++)
        {
            string name = list[i];
            string name2 = list[j];

            if (name > name2)
                lowIndex = j;
        }

        // Flip the elements if there was a value lower than i.
        if (i != lowIndex)
        {
            string temp = list[i];
            list[i] = list[lowIndex];
            list[lowIndex] = temp;
        }
    }
}
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das*_*ght 5

这是问题所在:这一行

string name = list[i];
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应该

string name = list[lowIndex];
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您当前的实现将jnot 的元素与您到目前为止找到的最小字符串进行比较,但是将其与index处的字符串进行比较i.这是不正确的,因为它找不到最小的剩余字符串:相反,它找到的最后一个字符串vector小于索引处的当前元素i,这不是你想要的.