static block instance block java Order

Question

阅读此问题在JVM中加载类时,类的不同部分以什么顺序初始化？和相关的JLS.我想更详细地了解为什么例如具有类Animal(超类)和类Dog(子类)如下:

class Animal
{
static{
System.out.println("This is Animal's static block speaking"):
}
{
System.out.println("This is Animal's instance block speaking");
}

class Dog{
static{
System.out.println("This is Dog's static block speaking");
}
{
System.out.println("This is Dog's instance block speaking");
}
public static void main (String [] args)
{
Dog dog = new Dog();
}
}

确定实例化类之前,需要初始化其直接超类(因此需要执行所有静态变量和块).所以基本上问题是:为什么在初始化超类的静态变量和静态块之后,控制下到静态变量初始化的子类,而不是完成实例成员的初始化？

控制如下:

superclass (Animal): static variables and static blocks
subclass (Dog): static variables and static blocks
superclass (Animal): instance variables and instance blocks
sublcass (Dog):instance variables and instance blocks

它是以这种方式而不是:

superclass -> static members
superclass -> instance members
subclass -> static members
sublcass-> instance members

Answer 1

为什么在初始化超类的静态变量和静态块之后,控制会转到静态变量初始化的子类,而不是完成实例成员的初始化？

因为静态初始化发生一次,所以在创建任何实例之前.

静态对应于类,非静态对应于特定实例.