Rik*_*ika 2 sql t-sql sql-server distinct
您好我的一个字段为空,我试图使用distinct来过滤掉重复的冗余和记录.这是我的SQL语句,它根据绘制而不是计算检查值!
SELECT CASE SUM(Money)
WHEN null THEN sum(0)
ELSE SUM(Money)
END AS MoneyTaken
FROM (SELECT Money
FROM tblPayment AS tblPayment_1
WHERE (CheckStatus = 0) AND (IDBuyer = @BuyerID) AND (IDSource = @SourceID)
GROUP BY ID, IDBuyer, IDSeller, Money) AS derivedtbl_1_1) AS [Cheques Which didnt have credit], tblPurchase.Price AS SellPrice
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但这不起作用,我仍然NULL在MoneyTaken执行函数时进入Column.
这是我的Full StoredProcedure,它仍然显示重复的结果:
ALTER PROCEDURE [dbo].[SGetListofKharIDBuyer]
@SurceId bigint,
@BuyerId bigint
AS
SET NOCOUNT ON;
/*
0 = check(cheque) dosent have credit-so couldntget money out of it
1 = check(cheque) has credit- got the money
-1 = in cashe - paid in cash
*/
SELECT distinct vPatmentForReport.Account, vPatmentForReport.PaymentStatus, vPatmentForReport.Description, vPatmentForReport.Bank, vPatmentForReport.Serial,
vPatmentForReport.PaymentMethod, vPatmentForReport.Date, vPatmentForReport.???? * Money AS [Payment in Cash], tblPurchase.Date AS [PurchaseDate],
tblReserve.Fee , tblReserve.NumberOfReserve , tblReserve.TotalMoney ,
(SELECT COALESCE( SUM(Money),0) AS [PaidMoney]
FROM (SELECT Money
FROM tblPardakht
WHERE (CheckStatus <> 0) AND (IDBuyer = @BuyerId) AND (IDSource = @SurceId)
GROUP BY ID, IDBuyer, IDAccount, Money) AS derivedtbl_1) AS [Sum of Cheques and in cash payments],
(SELECT COALESCE( SUM(Money),0) AS [PaidMoney]
FROM (SELECT Money
FROM tblPardakht AS tblPardakht_1
WHERE (CheckStatus = 0) AND (IDBuyer = @BuyerId) AND (IDSource = @SurceId)
GROUP BY ID, IDBuyer, IDAccount, Money) AS derivedtbl_1_1) AS [sum of cheques which are not drawn], tblPurchase.Money ,
tblReserve.Description , tblReserve.Date
FROM tblPurchase INNER JOIN
tblReserve ON tblPurchase.IDReserve = tblReserve.ID inner JOIN
vPatmentForReport ON tblReserve.IDSource = vPatmentForReport.[SourceId] AND tblReserve.IDBuyer = vPatmentForReport.[BuyerId]
WHERE (vPatmentForReport.[BuyerId] = @BuyerId) AND (vPatmentForReport.[SourceId] = @SurceId)
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vPatmentForReport 是一个由没有任何参数的函数构成的视图.
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