我目前正在使用一个控制台应用程序,我正在使用HttpClient与Apache CouchDB数据库进行交互.我正在使用这篇文章:http://www.asp.net/web-api/overview/web-api-clients/calling-a-web-api-from-a-net-client
当我通过PostAsJsonSync序列化并将文档发送到我的数据库时,我想忽略我的类中的null属性,但我不确定如何:
public static HttpResponseMessage InsertDocument(object doc, string name, string db)
{
HttpResponseMessage result;
if (String.IsNullOrWhiteSpace(name)) result = clientSetup().PostAsJsonAsync(db, doc).Result;
else result = clientSetup().PutAsJsonAsync(db + String.Format("/{0}", name), doc).Result;
return result;
}
static HttpClient clientSetup()
{
HttpClientHandler handler = new HttpClientHandler();
handler.Credentials = new NetworkCredential("**************", "**************");
HttpClient client = new HttpClient(handler);
client.BaseAddress = new Uri("*********************");
//needed as otherwise returns plain text
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
return client;
}
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这是我正在序列化的课程....
class TestDocument
{
public string Schema { get; set; }
public long Timestamp { get; set; }
public int Count { get; set; }
public string _rev { get; set; }
public string _id { get; set; } - would like this to be ignored if null
}
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任何帮助非常感谢.
Jul*_*obs 13
假设您使用Json.NET来序列化对象,您应该使用JsonProperty属性的NullValueHandling属性
[JsonProperty(NullValueHandling=NullValueHandling.Ignore)]
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Hel*_*ick 11
如果您需要此行为你要发送的(这正是导致我对这个问题的情况下)的类的所有属性,我认为这将是清洁:
using ( HttpClient http = new HttpClient() )
{
var formatter = new JsonMediaTypeFormatter();
formatter.SerializerSettings.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;
TestDocument value = new TestDocument();
HttpContent content = new ObjectContent<TestDocument>( value, formatter );
await http.PutAsync( url, content );
}
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这样就不需要为类添加属性了,您仍然不必手动序列化所有值.
小智 6
使用 HttpClient.PostAsync
JsonMediaTypeFormatter jsonFormat = new JsonMediaTypeFormatter();
jsonFormat.SerializerSettings.DefaultValueHandling = Newtonsoft.Json.DefaultValueHandling.Ignore;
jsonFormat.SerializerSettings.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;
HttpResponseMessage res = c.PostAsync<T>(url, TObj, jsonFormat).Result;
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