(Python)如果Else问题并列出到字符串转换问题

Question

我对编程很新,我被分配了一个将英文文本转换为Pig Latin的家庭作业.

我到目前为止的代码是:

VOWELS = ("a", "e", "i", "o", "u", "A", "E", "I", "O", "U")
def vowel_start(word):
     pig_latin = word + "ay"
     return pig_latin
def vowel_index(word):
     for i, letters in enumerate(word):
          if letters in VOWELS:
               vowel_index = i
               pig_latin = word[vowel_index:] + word[:vowel_index] + "ay"
               return pig_latin
          else:
               pig_latin = word   #The issue here is that even if the word
               return pig_latin   #has vowels, the program will still only
                                  #return the untranslated word as shown
                                  #in else.
english_text = raw_input("What do you want to translate?")
translate = english_text.split()

pig_latin_words = []
translated_text = "".join(str(pig_latin_words)) #The issue here is that the list
                                                #will not join with the string.

for i in translate:
     first = i[0]
     vow = False
     if first in VOWELS:
          vow = True
     if vow == True:
          pig_latin_words.append(vowel_start(i))
     else:
          pig_latin_words.append(vowel_index(i))

print "The text you translated is " + english_text
print "The translated text is " + translated_text #The issue here is that the program
                                                  #displays "The translated text is "
                                                  #and that's it

如果我注释掉def vowel_index函数的else方面,那么if方面就可以了.如果我把它留在程序中,if方面不再起作用.过去几天我一直试图解决这个问题,我不知道如何修复它.任何帮助将不胜感激,谢谢!

有关作业的更多详细信息:

• 如果单词以元音开头,请将单词保留为原样并在末尾添加"ay".
• 如果单词包含元音,但不包含元音,则取元音前的字母,将其移到单词的末尾,并在末尾添加"ay".
• 如果单词不包含任何元音,则将该单词保留为原样.

Answer 1

你的函数当前的编写方式,你将始终返回for循环的第一次迭代,基于第一个字符是元音与否.如果没有字符是元音,则需要遍历每个字符并仅返回单词不变.

首先删除else; 当你看到一个不是元音的单个字符时,你不想返回,因为后面的字符可能是一个元音.现在既然你有一个return声明if,你知道如果你到达循环的末尾而没有返回没有任何字符word是元音,那么你可以在for循环之外返回单词.例如:

def vowel_index(word):
    for i, letters in enumerate(word):
        if letters in VOWELS:
            vowel_index = i
            return word[vowel_index:] + word[:vowel_index] + "ay"
    return word

对于你的第二个问题,这里有几件事情.

首先,你需要移动创建,translated_text以便它pig_latin_words已经有了新单词.这将在你最后的印刷陈述之前.

此外,要将单词列表转换为由空格分隔的单个字符串,您应该使用以下内容:

translated_text = " ".join(pig_latin_words)

这是一个显示差异的简短示例:

>>> pig_latin_words = ['atcay', 'ogday']
>>> print "".join(str(pig_latin_words))  # your version
['atcay', 'ogday']
>>> print " ".join(pig_latin_words)      # my version
atcay ogday