Bha*_*ani 5 android broadcastreceiver wifi android-intent
当用户进入具有Wi-Fi的区域时,如何打开我的应用程序?这可能吗?假设我的应用程序处于onPause()状态(表示我的设备的主屏幕).现在当设备连接wifi时.它会自动打开我的应用程序.
小智 5
尝试添加广播接收器并收听网络更改,当wi-fi连接启动您的活动时.像这个解决方案的东西
public class ConnectivityReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
ConnectivityManager connMgr = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo wifi = connMgr.getNetworkInfo(ConnectivityManager.TYPE_WIFI);
NetworkInfo mobile = connMgr.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
if (((null != wifi)&&(wifi.isAvailable())) || ((null != mobile)&&(mobile.isAvailable()))){
Intent uplIntent = new Intent(context, YourActivity.class);
uplIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(uplIntent);
}
}
}
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并添加到清单
<receiver android:name=".receiver.ConnectivityReceiver">
<intent-filter>
<action android:name="android.net.conn.CONNECTIVITY_CHANGE" />
</intent-filter>
</receiver>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>
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