用PHP计算传递时间

Question

我得到了这样的日期之间的时差:

$time1 = "2013-02-25 12:00:00";
$time2 = "2013-01-01 12:00:00";
$tdiff = strtotime($time1) - strtotime($time2);

我想要提取日,小时和分钟$tdiff.输出应该像:35 days 6 hours 14 minutes

我真的搜索并尝试自己做点什么.但我无法获得真正的价值.

----编辑----我可以找到日期差异.我想从计算时间中提取天数,小时数,分钟数......

----编辑2 ----这是我完整的mysql代码

select (
    select avg(UNIX_TIMESTAMP(tarih)) from table1 
    where action in (6) and who = '".$user."' and dates between '".$date1."' and '".$date."'
    ) - ( 
    select avg(UNIX_TIMESTAMP(tarih_saat)) from table2 
    where action in (6) and active = 1 and dates between '".$date1."' and '".$date2."
)

此查询返回真实的时间值.此查询对我来说正常.结果如下:215922.结果类型为UNIX_TIMESTAPM.所以我想知道这个时间戳中有多少天,几小时和几分钟.

Answer 1

PHP有一个DateInterval类,可以这样使用:

$date1 = new DateTime('2013-02-25 12:00:00');
$date2 = new DateTime('2013-01-01 12:00:00');

$diff = $date2->diff($date1); // Get DateInterval Object

echo $diff->format('%d Day and %h hours and %m minutes');