我有两张桌子
Bills: id amount reference
Transactions: id reference amount
以下SQL查询
SELECT
*,
(SELECT SUM(amount)
FROM transactions
WHERE transactions.reference = bils.reference) AS paid
FROM bills
GROUP BY id HAVING paid<amount
Run Code Online (Sandbox Code Playgroud)
意味着来自表的某些行Bills,添加一个列paid,其中包含相关事务量的总和.
但是,它仅在每个账单至少有一笔交易时才有效.否则,不返回无交易账单的行.
也许,那是因为我应该做一个内部联接!
所以我尝试以下方法:
SELECT
*,
(SELECT SUM(transactions.amount)
FROM transactions
INNER JOIN bills ON transactions.reference = bills.reference) AS paid
FROM bills
GROUP BY id
HAVING paid < amount
Run Code Online (Sandbox Code Playgroud)
但是,这会为所有行返回相同的pay值!我究竟做错了什么 ?
Guf*_*ffa 17
使用左连接而不是子查询:
select b.id, b.amount, b.paid, sum(t.amount) as transactionamount
from bills b
left join transactions t on t.reference = b.reference
group by b.id, b.amount, b.paid
having b.paid < b.amount
Run Code Online (Sandbox Code Playgroud)
编辑:
要将事务总和与金额进行比较,请处理没有事务时获得的空值:
having isnull(sum(t.amount), 0) < b.amount
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
77811 次 |
| 最近记录: |