C#代码仅在步骤中给出预期结果？

Question

好的,我有一个骰子扔应用程序...

当我逐步执行代码时,它正常运行,'结果'包含正确的投掷结果数,并且它们看起来是随机的,当我让代码运行并完全相同的事情它产生一组相同的数字.

我确信这是一个逻辑错误,我看不到,但摆弄它好几个小时并没有改善情况,所以任何帮助都很有帮助.:)

    class Dice
{

    public int[] Roll(int _throws, int _sides, int _count)
    {
        Random rnd = new Random();
        int[] results = new int[_throws];
        // for each set of dice to throw pass data to calculate method
        for (int i = 0; i < _throws; i++)
        {
            int thisThrow = Calculate(_sides, _count);
            //add each throw to a new index of array... repeat for every throw
            results[i] = thisThrow; 
        }

        return results;
    }


    private int Calculate(int _sides, int _count)
    {
        Random rnd = new Random();
        int[] result = new int[_count];
        int total = 0;
        //for each dice to throw put data into result
        for (int i = 0; i < _count; i++)
        {
            result[i] = rnd.Next(1, _sides);
        }
        //count the values in result
        for (int x = 0; x < _count; x++)
        {
            total = total + result[x];
        }
        //return total of all dice to Roll method
        return total;
    }
}

Answer 1

第一个错误:永远不要使用Random的多个实例,使用单个实例,并将其与其他参数一起传递.

Answer 2

当你创建"Random rnd = new Random();"时 它是按当前时间播种的.当您调试代码(需要时间)时,每次都会以不同的方式播种.

创建1个Random实例,并在任何地方引用它.