foreach($行为$ row)无法添加html标记

Question

从这个问题开始现在我需要设置输出样式才发现php不喜欢我的放置标签的方式我也尝试将其封装在"和.或<?php $row['field'] ?>但仍然无效.

    <table class="table table-hover">
<caption>List All Customers from Customer Table</caption>
<thead>
<tr>
<th>id</th>
<th>Inital</th>
<th>First Name</th>
<th>Last Name</th>
<th>Mobile</th>
<th>Landline</th>
<th>Email</th>
<th>Address</th>
<th>Post Code</th>
</tr>
 </thead>
<tbody>
<tr>
<?php
foreach ($rows as $row) { 
?>
 <td><?php $row['clientid']; ?></td>
 <td><?php $row['inital']; ?></td> 
 <td><?php $row['firstname']; ?></td>
 <td><?php $row['lastname']; ?></td>
 <td><?php $row['mobile']; ?></td>
 <td><?php $row['landline']; ?></td>
 <td><?php $row['email']; ?></td>
 <td><?php $row['address']; ?></td>
 <td><?php $row['postcode']; ?></td>
 <?php } ?>
</tr>
</tbody>
</table>

它不起作用,没有结果.:(拔出头发!看着其他问题,但北方足够清楚.

Answer 1

添加echo..

<td><?php echo $row['clientid']; ?></td>
<td><?php echo $row['inital']; ?></td> 
<td><?php echo $row['firstname']; ?></td>
<td><?php echo $row['lastname']; ?></td>
<td><?php echo $row['mobile']; ?></td>
<td><?php echo $row['landline']; ?></td>
<td><?php echo $row['email']; ?></td>
<td><?php echo $row['address']; ?></td>
<td><?php echo $row['postcode']; ?></td>