哑巴引用智能引号Javascript问题

Question

我有一些JavaScript代码可以将愚蠢的引号转换为智能引号contenteditable.

当您在它们仅关闭的行的开头添加哑引号时,会出现此问题.例如,你得到这个:

”dumb quotes” instead of “dumb quotes”

试试演示:http://jsfiddle.net/7rcF2/

我正在使用的代码:

function replace(a) {
    a = a.replace(/(^|[-\u2014\s(\["])'/g, "$1\u2018");       // opening singles
    a = a.replace(/'/g, "\u2019");                            // closing singles & apostrophes
    a = a.replace(/(^|[-\u2014/\[(\u2018\s])"/g, "$1\u201c"); // opening doubles
    a = a.replace(/"/g, "\u201d");                            // closing doubles
    a = a.replace(/--/g, "\u2014");                           // em-dashes
return a  };

有任何想法吗？谢谢!

PS我很喜欢正则表达式......

Answer 1

试试这个:

var a = '"dumb quotes" instead -- of "dumb quotes", fixed it\'s';

 a = a.replace(/'\b/g, "\u2018")     // Opening singles
      .replace(/\b'/g, "\u2019")     // Closing singles
      .replace(/"\b/g, "\u201c")     // Opening doubles
      .replace(/\b"/g, "\u201d")     // Closing doubles
      .replace(/--/g,  "\u2014")     // em-dashes
      .replace(/\b\u2018\b/g,  "'"); // And things like "it's" back to normal.
// Note the missing `;` in these lines. I'm chaining the `.replace()` functions.  

输出:

'“dumb quotes” instead — of “dumb quotes”, fixed it's'

基本上,你正在寻找单词边界:\b

这是一个更新的小提琴