在metroapp中显示存储在存储文件中的图片

Question

我想通过绑定显示存储在StorageFile中的图片的内容,但无论我想要做什么它似乎都不起作用.

以下是我已经测试过的两个解决方案:

string img =( await CompetencesFolder.GetFileAsync(FormatImageNameToFileName(imageName))).Path;

然后通过绑定将获得的路径(文件的完整绝对路径)返回到源Property,并且:

 BitmapImage img = await LoadImage(await CompetencesFolder.GetFileAsync(FormatImageNameToFileName(imageName)));

  private static async Task<BitmapImage> LoadImage(StorageFile file)
        {
            BitmapImage bitmapImage = new BitmapImage();
            FileRandomAccessStream stream = (FileRandomAccessStream)await file.OpenAsync(FileAccessMode.Read);

            bitmapImage.SetSource(stream);


            return bitmapImage;

        }

稍后将最终的bitmapImage返回到我的binded属性.

这些方法都不起作用..

有人有想法吗？

编辑:修复

这是解决问题的代码:

BitmapImage img = new BitmapImage() { UriSource = new Uri( LOCAL_REPOSITORY.Path + "/Assets/gfx/cards/" + FormatImageNameToFileName(imageName) + ".jpg", UriKind.RelativeOrAbsolute) };

我做了2个样品的混合上面:我创造了我的BitmapImage从图片的绝对URI(LOCAL_REPOSITORY包含本地存储的参考:ApplicationData.Current.LocalFolder)

我仍然无法理解为什么其他两种方法失败:我通常将我的图像直接绑定到Uri,字符串或BitmapImage,它可以工作..

Answer 1

下面的代码显示了如何在app中使用loadimage方法:创建一个空白应用程序,将一个Image和一个Button添加到主页面.

    private async void  Button_Click_1(object sender, RoutedEventArgs e)
    {
        // load file from document library. Note: select document library in capabilities and declare .png file type
        string filename = "Logo.png";
        Windows.Storage.StorageFile sampleFile = await Windows.Storage.KnownFolders.DocumentsLibrary.GetFileAsync(filename);
        // load file from a local folder
        //Windows.Storage.StorageFile sampleFile = sampleFile = await Windows.ApplicationModel.Package.Current.InstalledLocation.GetFileAsync("Assets\\Logo.png");

        BitmapImage img = new BitmapImage();
        img = await LoadImage(sampleFile);
        myImage.Source = img;
    }

    private static async Task<BitmapImage> LoadImage(StorageFile file)
    {
        BitmapImage bitmapImage = new BitmapImage();
        FileRandomAccessStream stream = (FileRandomAccessStream)await file.OpenAsync(FileAccessMode.Read);

        bitmapImage.SetSource(stream);

        return bitmapImage;

    }