grep表示日志文件中不包含某个单词的行

Question

我正在尝试分析日志文件.我正在寻找一个正则表达式,它满足以下要求:

LOG: https://localhost/a
LOG: https://remotehost/x
LOG: https://localhost/b
LOG: https://localhost/c
LOG: https://remotehost/a

以上是日志文件的示例.问题:如何通过日志文件进行grep,这样我只得到不包含的行:

https://localhost

结果应该是:

LOG: https://remotehost/x
LOG: https://remotehost/a

Answer 1

使用 grep -v <word> <filename>

从grep手册(FreeBSD):

-v, --invert-match
    Invert the sense of matching, to select non-matching lines.