Python CSV错误:预期的序列

Ben*_*oms 16 python csv

我试图在Python中运行以下代码,并收到错误:

 csv.Error: sequence expected
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有谁知道我的代码有什么问题?(该文件先前已导入程序).

import csv
file = open('/home/btoms/Desktop/TomsBen/2000/01/01/20000101acme.mts', 'r')

variables = []

file.readline() #Skip a line
file.readline() 
file.readline() #Skip another line

for line in file:
    tmp = line.split()
    tmp_STID = str(tmp[0])
    tmp_T = float(tmp[4]) 
    tmp_RH = float(tmp[3])
    tmp_Times = float(tmp[2])
    variables.append(tmp_STID)
    variables.append(tmp_Times)
    variables.append(tmp_T)
    variables.append(tmp_RH)


    if tmp_T < 6.2 and tmp_RH > 60.0: 
    dataCSV = open('ProgramCheck.csv', 'w') 
    writer = csv.writer(dataCSV, dialect='excel')
    writer.writerow(['Station ID', 'Time', 'Temperature' , 'Relative Humidity']) 

    for values in variables:
        writer.writerow(values)
    else:
            pass
    file.close()
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错误出现为:

    Traceback (most recent call last):
      File "checkcsv.py", line 30, in <module>
        writer.writerow(values)
    _csv.Error: sequence expected
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Mik*_*one 16

writer.writerow期望值的序列(元组或列表)写入单行,该行中每列一个值.你给它的是一个单一的价值.您的代码应该看起来更像:

writer.writerow([tmp_STID, tmp_Times, tmp_T, tmp_RH])
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并且在我看来,大多数代码应该是一个大循环,每个站运行一次(因此每行一次).


dataCSV = open('ProgramCheck.csv', 'w') 
writer = csv.writer(dataCSV, dialect='excel')
writer.writerow(['Station ID', 'Time', 'Temperature' , 'Relative Humidity']) 

for line in inputData:
    tmp = line.split()

    tmp_STID = str(tmp[0])
    tmp_T = float(tmp[4]) 
    tmp_RH = float(tmp[3])
    tmp_Times = float(tmp[2])

    if tmp_T < 6.2 and tmp_RH > 60.0: 
        writer.writerow([tmp_STID, tmp_Times, tmp_T, tmp_RH])

file.close()
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dm0*_*514 2

现在看起来你只是想写一个字符串

\n\n
  writer.writerow(variables)\n
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将写入整行

\n\n
 tmp_STID = str(tmp[0])\n\xc2\xa0 \xc2\xa0 tmp_T = float(tmp[4])\xc2\xa0\n\xc2\xa0 \xc2\xa0 tmp_RH = float(tmp[3])\n\xc2\xa0 \xc2\xa0 tmp_Times = float(tmp[2])\n
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检查变量列表

\n\n
[tmp_STID, tmp_T, tmp_RH, tmp_Time]\n
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看起来您正在为每次迭代打开一个新的 csv 文件?应该脱离循环吗?

\n