格式化EditText视图以获取电话号码

Question

我有一个EditText视图,我希望它将用户的输入格式化为电话号码格式.例如,当用户键入1234567890时,EditText视图应在输入前3个数字后立即动态显示为"(123)456-7890".

我在OnCreate中尝试了以下内容,但它似乎对我没有任何作用......

EditText ET = (EditText) findViewById(R.id.add_number);
ET.addTextChangedListener(new PhoneNumberFormattingTextWatcher());

如何让用户的输入以电话号码格式显示？

Answer 1

使用此代码,您可以制作自定义TextWatcher并制作您想要的任何格式:

ET.addTextChangedListener(new PhoneNumberFormattingTextWatcher() {
        //we need to know if the user is erasing or inputing some new character
        private boolean backspacingFlag = false;
        //we need to block the :afterTextChanges method to be called again after we just replaced the EditText text
        private boolean editedFlag = false;
        //we need to mark the cursor position and restore it after the edition
        private int cursorComplement;

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
            //we store the cursor local relative to the end of the string in the EditText before the edition
            cursorComplement = s.length()-ET.getSelectionStart();
            //we check if the user ir inputing or erasing a character
            if (count > after) {
                backspacingFlag = true;
            } else {
                backspacingFlag = false;
            }
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            // nothing to do here =D
        }

        @Override
        public void afterTextChanged(Editable s) {
            String string = s.toString();
            //what matters are the phone digits beneath the mask, so we always work with a raw string with only digits
            String phone = string.replaceAll("[^\\d]", "");

            //if the text was just edited, :afterTextChanged is called another time... so we need to verify the flag of edition
            //if the flag is false, this is a original user-typed entry. so we go on and do some magic
            if (!editedFlag) {

                //we start verifying the worst case, many characters mask need to be added
                //example: 999999999 <- 6+ digits already typed
                // masked: (999) 999-999
                if (phone.length() >= 6 && !backspacingFlag) {
                    //we will edit. next call on this textWatcher will be ignored
                    editedFlag = true;
                    //here is the core. we substring the raw digits and add the mask as convenient
                    String ans = "(" + phone.substring(0, 3) + ") " + phone.substring(3,6) + "-" + phone.substring(6);
                    ET.setText(ans);
                    //we deliver the cursor to its original position relative to the end of the string
                    ET.setSelection(ET.getText().length()-cursorComplement);

                //we end at the most simple case, when just one character mask is needed
                //example: 99999 <- 3+ digits already typed
                // masked: (999) 99
                } else if (phone.length() >= 3 && !backspacingFlag) {
                    editedFlag = true;
                    String ans = "(" +phone.substring(0, 3) + ") " + phone.substring(3);
                    ET.setText(ans);
                    ET.setSelection(ET.getText().length()-cursorComplement);
                }
            // We just edited the field, ignoring this cicle of the watcher and getting ready for the next
            } else {
                editedFlag = false;
            }
        }
    });

确保将XML中的EditText Lenght限制为14个字符

<EditText
    android:id="@+id/editText_phone"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:inputType="phone"
    android:lines="1"
    android:maxLength="14"/>

Answer 2

步骤1：此处是XML文件中输入字段的代码。

 <EditText
    android:id="@+id/editText_phone"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:inputType="phone"
    android:lines="1"
    android:maxLength="14"/>

步骤2：这是添加到MainFile.java中的代码

 phoneNo = (EditText)findViewById(R.id.editText_phone);
 phoneNo.addTextChangedListener(new PhoneNumberFormattingTextWatcher());

输出：它将给您类似(123)456-7890的数字

Answer 3

尝试这个

PhoneNumberFormattingTextWatcher() 方法不起作用我尝试分配最后我得到了解决方案

1. 在你的 xml 文件中粘贴这个

   <EditText
   android:id="@+id/editTextId"
   android:layout_height="wrap_content"
   android:layout_width="match_parent"
   android:inputType="phone"
   android:digits="0123456789+" />
   

2. 在你的 oncreate 方法中粘贴这个

   final EditText editText = (EditText) findViewById(R.id.editTextId);
   editText.addTextChangedListener(new TextWatcher()
   {
       @Override
       public void onTextChanged(CharSequence s, int start, int before, int count)
       {
           // TODO Auto-generated method stub
       }
   
       @Override
       public void beforeTextChanged(CharSequence s, int start, int count, int after)
       {
           // TODO Auto-generated method stub
       }
       @Override
       public void afterTextChanged(Editable s)
       {
           String text = editText.getText().toString();
           int  textLength = editText.getText().length();
           if (text.endsWith("-") || text.endsWith(" ") || text.endsWith(" "))
               return;
           if (textLength == 1) {
               if (!text.contains("("))
               {
                   editText.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
                   editText.setSelection(editText.getText().length());
               }
           }
           else if (textLength == 5)
           {
               if (!text.contains(")"))
               {
                   editText.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
                   editText.setSelection(editText.getText().length());
               }
           }
           else if (textLength == 6)
           {
               editText.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
               editText.setSelection(editText.getText().length());
           }
           else if (textLength == 10)
           {
               if (!text.contains("-"))
               {
                   editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                   editText.setSelection(editText.getText().length());
               }
           }
           else if (textLength == 15)
           {
               if (text.contains("-"))
               {
                   editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                   editText.setSelection(editText.getText().length());
               }
           }
           else if (textLength == 18)
           {
               if (text.contains("-"))
               {
                   editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                   editText.setSelection(editText.getText().length());
               }
           }
       }
   });
   

输出：-

Answer 4

我做了一些组合，我将输入类型修改为电话，然后使用正则表达式删除所有非数字字符：phonenumber = Phonenumber.replaceAll("\D", "");