两个给定时间之间的当前时间是？

Question

我正在尝试计算当前时间是否在餐馆的营业时间内.

Stackoverflow上已经提出了很多这个问题,但是我没有找到一个可以解决我遇到的问题的问题.此外,很高兴看到更好的方法来做到这一点的想法.

目前,如果关闭一天(本例中为星期日)或者如果是"星期六"凌晨1点(因此技术上是凌晨1点),它就会中断.我有一种感觉,我必须在午夜之后改变存储数据的方式,但我正在尝试使用我现在拥有的东西.这是一个问题,因为大多数餐馆列出他们的开放时间为下午5点 - 凌晨2点,而不是下午5点 - 早上12点,早上12点 - 凌晨2点.

无论如何,这就是我所拥有的.请告诉我一个更好的方法.

我有时间像这样存储:

$times = array(
    'opening_hours_mon' => '9am - 8pm',
    'opening_hours_tue' => '9am - 2am',
    'opening_hours_wed' => '8:30am - 2am',
    'opening_hours_thu' => '5:30pm - 2am',
    'opening_hours_fri' => '8:30am - 11am',
    'opening_hours_sat' => '9am - 3pm, 5pm - 2am',
    'opening_hours_sun' => 'closed'
);

这是我现在使用的代码:

// Get the right key for today
$status = 'open';
$now = (int) current_time( 'timestamp' );
$day = strtolower( date('D', $now) );
$string = 'opening_hours_'.$day;

$times = $meta[$string][0]; // This should be a stirng like '6:00am - 2:00am' or even '6:00am - 11:00am, 1:00pm to 11:00pm'.

// Does it contain a '-', if not assume it's closed.
$pos = strpos($times, '-');
if ($pos === false) {       
    $status = 'closed';
} else {

    // Maybe a day has multiple opening times?
    $seating_times = explode(',', $times);
    foreach( $seating_times as $time ) {

        $chunks = explode('-', $time);
        $open_time = strtotime($chunks[0]);
        $close_time = strtotime($chunks[1]);

        // Calculate if now is between range of open and closed
        if(($open_time <= $now) && ($now <= $close_time)) {
            $status = 'open';
            break;
        } else {
            $status = 'closed';             
        }

    }

}

注意:current_time('timestamp',0)是一个WordPress函数.

Answer 1

这是我的面向对象的解决方案，基于 PHP DateTime 类的使用（自 5.2 版本起可用）：

<?php 

class Restaurant {
    private $cw;
    private $times = array();
    private $openings = array();

    public function __construct(array $times) {
        $this->times = $times;
        $this->setTimes(date("w") ? "this" : "last");
        //print_r($this->openings);       // Debug
    }

    public function setTimes($cw) {
        $this->cw = $cw;
        foreach ($this->times as $key => $val) {
            $t = array();
            $buf = strtok($val, ' -,');
            for ($n = 0; $buf !== FALSE; $n++) {
                try {
                    $d = new DateTime($buf);
                    $d->setTimestamp(strtotime(substr($key, -3)." {$this->cw} week {$buf}"));
                    if ($n && ($d < $t[$n-1])) {
                        $d->add(new DateInterval('P1D'));
                    }
                    $t[] = $d;
                } catch (Exception $e) {
                    break;
                }
                $buf = strtok(' -,');
            }
            if ($n % 2) {
                throw new Exception("Invalid opening time: {$val}");
            } else {
                $this->openings[substr($key, -3)] = $t;
            }
        }
    }

    public function isOpen() {
        $cw = date("w") ? "this" : "last";
        if ($cw != $this->cw) {
            $this->setTimes($cw);
        }
        $d = new DateTime('now');
        foreach ($this->openings as $wd => $t) {
            $n = count($t);
            for ($i = 0; $i < $n; $i += 2) {
                if (($d >= $t[$i]) && ($d <= $t[$i+1])) {
                    return(TRUE);
                }
            }
        }
        return(FALSE);
    }
}

$times = array(
    'opening_hours_mon' => '9am - 8pm',
    'opening_hours_tue' => '9am - 2am',
    'opening_hours_wed' => '8:30am - 2am',
    'opening_hours_thu' => '9am - 3pm',
    'opening_hours_fri' => '8:30am - 11am',
    'opening_hours_sat' => '9am - 3pm, 5pm - 2am',
    'opening_hours_sun' => 'closed'
);

try {
    $r = new Restaurant($times);
    $status = $r->isOpen() ? 'open' : 'closed';
    echo "status=".$status.PHP_EOL;
} catch (Exception $e) {
    echo $e->getMessage().PHP_EOL;
}

?>

正如您所看到的，构造函数构建了一个内部表单（openingsDateTime 对象的数组），然后在方法中使用该表单进行简单比较，isOpen以检查在调用时餐厅是否打开或关闭。

您还会注意到，我使用了DateTime:add方法来计算明天的日期，而不是将 86400 (24*60*60) 添加到当前日期时间戳，以避免DST时移问题。
概念证明：

<?php

ini_set("date.timezone", "Europe/Rome");
echo "date.timezone = ".ini_get("date.timezone").PHP_EOL;

$d1 = strtotime("2013-10-27 00:00:00");
$d2 = strtotime("2013-10-28 00:00:00");
// Expected: 86400, Result: 90000
echo "Test #1: ".($d2 - $d1).PHP_EOL;
// Expected: 2013-10-28 00:00:00, Result: 2013-10-27 23:00:00
echo "Test #2: ".date("Y-m-d H:i:s", $d1 + 86400).PHP_EOL;

$d1 = strtotime("2014-03-30 00:00:00");
$d2 = strtotime("2014-03-31 00:00:00");
// Expected: 86400, Result: 82800
echo "Test #3: ".($d2 - $d1).PHP_EOL;
// Expected: 2014-03-30 00:00:00, Result: 2014-03-29 23:00:00
echo "Test #4: ".date("Y-m-d H:i:s", $d2 - 86400).PHP_EOL;

?>

给出以下结果：

date.timezone = Europe/Rome
Test #1: 90000
Test #2: 2013-10-27 23:00:00
Test #3: 82800
Test #4: 2014-03-29 23:00:00

因此，似乎一天并不总是有86400秒；至少一年不会两次...