每次加载下一张图像之前,第一张图像都会变得可见

Question

这是我的网站http://www.alienchela.com/portfolio.html.

首先单击任何客户端图像即可.

但是,如果你每次点击下一个按钮,你就可以看到.首先是前一个图像,然后下一个图像加载.

这是代码:

var ticker = $('.img_wrap');
            $('.next').click(function () {
                $('.img_panel:visible').fadeOut(1000, function() {
                        $(this).appendTo(ticker);
                        ticker.children().first().show(function(){
                            var artit = $(this).attr('title');
                            $(this).load(artit+'.txt');
                });
                    });
                $(ticker).hide().delay(1500).fadeIn(1000);
            });

我做了一个黑客.我做了一些延迟过渡.

$(ticker).hide().delay(1500).fadeIn(1000); 

JS不是很好.

任何帮助表示赞赏.

Answer 1

干得好:

分析

1.初始状态

<div class="img_wrap">
    <div class="img_panel" title="pixi">pixi</div>
    <div class="img_panel" title="mus">mus</div>
    <div class="img_panel" title="flash">flash</div>
    <div class="img_panel" title="dir">dir</div>
    <div class="img_panel" title="rpi">rpi</div>
    <div class="img_panel" title="ac">ac</div>
    <div class="img_panel" title="css">css</div>
    <div class="img_panel" title="nagraj">nagraj</div>
</div>

2.点击"AC"

<div class="img_wrap">
    <div class="img_panel" title="pixi">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="mus">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="flash">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="dir">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="rpi">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="ac" style="display: block;">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="css">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
    <div class="img_panel" title="nagraj">
        <img src="img/clients/ac/ac_top.jpg" width="1040" height="217" alt="aucourant"><img src="img/clients/ac/ac1.jpg" width="1040" height="502" alt="aucourant">
    </div>
</div>

说明

每个img_panel都有"AC"的标题图像.而且他们没有CSS display:none;,这意味着那些div是可见的.执行时

$('.img_panel:visible').fadeOut(1000, function() {
    $(this).appendTo(ticker);
    ticker.children().first().show(function(){
        var artit = $(this).attr('title');
        $(this).load(artit+'.txt');
});

隐藏当前项目,然后显示下一个项目.在过渡期间,当前和下一个项目将被部分隐藏,并且背景div中的图像显示.

问题代码

$('.work li').click(function(){
    var clientitle = $(this).attr('title');
    $('.work').fadeOut(500), $('.big_images').delay(500).fadeIn();
    $('.img_panel[title="'+clientitle+'"]').fadeIn();
    var cltxt = clientitle+'.txt'
    $('.img_panel').load(cltxt);
});

解

// Only load data to active div
$('.img_panel[title="' + clientitle + '"]').load(cltxt);

此外,最好这样做:

// Hide all divs
$('.img_panel').hide();
// Load and unhide active div
$('.img_panel[title="' + clientitle + '"]').load(cltxt).show();

问题2

当您单击"AC"然后单击时Next,代码变为:

<div class="img_wrap" style="display: block;">
    <div class="img_panel" title="pixi" style="display: block;">...</div>
    <div class="img_panel" title="mus">...</div>
    <div class="img_panel" title="flash">...</div>
    <div class="img_panel" title="dir">...</div>
    <div class="img_panel" title="rpi">...</div>

    <div class="img_panel" title="css">...</div>
    <div class="img_panel" title="nagraj">...</div>
    <div class="img_panel" title="ac" style="display: none;">...</div>
</div>

看,ac元素到了最后,使下一次迭代的顺序错误.

解

无需重新排列div元素.只需使用一组标题和一个索引来处理next和prev.