我有一个女性和男性名字的列表,然后是数组中的姓氏列表.
我试图做的是使用随机生成器在这些数组中取这些名称,并根据我的调用输出随机的名字和姓氏.
在我完成之后,我将在其他类中引用该方法,而不是每次都写出来.
这是我到目前为止的代码:
private void RandName()
{
string[] maleNames = new string[1000] { "aaron", "abdul", "abe", "abel", "abraham", "adam", "adan", "adolfo", "adolph", "adrian"};
string[] femaleNames = new string[1000] { "abby", "abigail", "adele", "adrian"};
string[] lastNames = new string[1000] { "abbott", "acosta", "adams", "adkins", "aguilar"};
Random rand = new Random(DateTime.Now.Second);
if (rand.Next(1, 2) == 1)
{
FirstName = maleNames[rand.Next(0, maleNames.Length - 1)];
}
else
{
FirstName = femaleNames[rand.Next(0, femaleNames.Length - 1)];
}
}
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我的问题是:如何使用我创建的名称数组创建随机名称生成器?
public static string GenerateName(int len)
{
Random r = new Random();
string[] consonants = { "b", "c", "d", "f", "g", "h", "j", "k", "l", "m", "l", "n", "p", "q", "r", "s", "sh", "zh", "t", "v", "w", "x" };
string[] vowels = { "a", "e", "i", "o", "u", "ae", "y" };
string Name = "";
Name += consonants[r.Next(consonants.Length)].ToUpper();
Name += vowels[r.Next(vowels.Length)];
int b = 2; //b tells how many times a new letter has been added. It's 2 right now because the first two letters are already in the name.
while (b < len)
{
Name += consonants[r.Next(consonants.Length)];
b++;
Name += vowels[r.Next(vowels.Length)];
b++;
}
return Name;
}
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好吧,在不知道您面临的问题的情况下,这有点盲目,但我认为您的问题是您已将数组大小声明为1000,但在每个数组中只输入了大约 10 个值。因此,您的数组仅占满 1%,因此您将大部分获得空名称。
请尝试以下操作:
// Note I have not specified the array size.
string[] maleNames = {"aaron", "abdul", "abe", "abel", "abraham", "adam", "adan", "adolfo", "adolph", "adrian"};
string[] femaleNames = {"abby", "abigail", "adele", "adrian"};
string[] lastNames = {"abbott", "acosta", "adams", "adkins", "aguilar"};
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我猜你的随机发生器的结果每次都是一样的..
如果这是您的问题,则不应rand每次都创建局部变量.改为创建字段.
Smth喜欢:
private static Random rand = new Random(DateTime.Now.Second);
private void RandName()
{
...
}
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