Oracle在空格之前获取子字符串

Question

我有一个中间有空格的字符串,我需要在空格之前得到第一个字符串(可以是数字).

 WITH test_data AS (
  SELECT '123642134  10' AS quarter_cd FROM dual UNION ALL --VALID
)

 select *
  from test_data
 where regexp_like(quarter_cd, '', 'c')

输出应该是:

123642134

Answer 1

Substr (quarter_cd, 1,instr(quarter_cd,' ') - 1)

应该这样做.