ope*_*sas 4 javascript regex json date
我不是正则表达式专家,所以我正在寻求帮助以使正则表达式像这样工作:
var regExp = ???
regExp.exec('\/Date(1330848000000-0800)\/') = [..., '1330848000000', '0800']
// optional gmt
regExp.exec('\/Date(1330848000000)\/') = [..., '1330848000000', null]
regExp.exec('\/Date(1)\/') = [..., '1', null]
// gmt required if - is present
regExp.exec('\/Date(1330848000000-)\/') = null
// escaping backslash is required
regExp.exec('/Date(1330848000000-0800)\/') = null
regExp.exec('\/Date(1330848000000-0800)/') = null
// case sensitive
regExp.exec('\/date(1330848000000-0800)\/') = null
// only numbers allowed
regExp.exec('\/Date(1aaa848000000-0800)\/') = null
regExp.exec('\/Date(1330848000000-0a00)\/') = null
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我很早就被这样愚蠢的东西卡住了:
/\\bla(.*)bla/.exec('\bla123bla') = null // instead of [ ..., '123']
new RegExp('\\\\bla(.*)bla').exec('\bla123bla') = null // instead of [ ..., '123']
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如果字符串从时间和时区中不含任何其他数字,则可以使用此正则表达式:
/(\d+)(?:-(\d+))?/
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Putting into your code:
var regex = /(\d+)(?:-(\d+))?/;
// regex.exec...
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If you really need to validate and extract the numbers out of the string:
/^\/Date\((\d+)(?:-(\d+))?\)\/$/
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The regex above will check that the string follows the exact format, and also extract the numbers out.
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