Gam*_*aPL 0 php foreach return function
我有问题.在我的函数中,return只显示来自服务器的第一个玩家.我想向服务器显示所有玩家,但我无法让这个工作.这是我的代码:
function players() {
require_once "inc/SampQueryAPI.php";
$query = new SampQueryAPI('uh1.ownserv.pl', 25052); // Zmie? dane obok! //
if($query->isOnline())
{
$aInformation = $query->getInfo();
$aServerRules = $query->getRules();
$aPlayers = $query->getDetailedPlayers();
if(!is_array($aPlayers) || count($aPlayers) == 0)
{
return 'Brak graczy online';
}
else
{
foreach($aPlayers as $sValue)
{
$playerid = $sValue['playerid'];
$playername = htmlentities($sValue['nickname']);
$playerscore = $sValue['score'];
$playerping = $sValue['ping'];
return '<li>'.$playername.' (ID: '.$playerid.'), Punkty ('.$playerscore.'), Ping ('.$playerping.')</li>';
}
}
}
}
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你是在循环中返回的.
相反,您应该连接每次迭代的结果,然后在循环外返回该连接字符串.
例如
$result = "";
foreach($aPlayers as $sValue) {
# add to $result...
}
return $result
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