学习Python Splits和Joins?

Mic*_*uts 1 python split join list-comprehension python-2.7

我以为我理解python中的分裂和连接,但它不适合我.

让我们说的价值 inp[17] = 'Potters Portland Oregon school of magic'

# a string of data I am pulling from a csv file, the data comes through just fine.
loc = inp[17] 

l = loc.split(' ') # I want to split by the space

# I want to filter out all these words say they don't always 
# come as "School of magic" so I cant just filter that out they 
# could be mixed around at times.

locfilter = ['Potters', 'School', 'of', 'magic']     
locname = ' '.join([value for value in l if l not in locfilter])
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此时我的locname变量应该只包含Portland Oregon在其中,但它仍然'Potters Portland Oregon school of magic'没有过滤掉它.

我做错了什么我觉得问题出在我的脑海里locname =.

谢谢你的帮助.

aba*_*ert 5

这里的问题不是你的,split或者join只是你的列表理解条件中的一个愚蠢的错误(我们所有人一直在做的那种愚蠢的错误):

locname = ' '.join([value for value in l if l not in locfilter])
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显然l永远不会locfilter.如果你解决了这个问题:

locname = ' '.join([value for value in l if value not in locfilter])
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它工作正常:

'Portland Oregon school'
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请注意,'school'它仍然是输出的一部分.那是因为'school'不在locfilter; 'School'是.如果你想匹配这些不区分大小写:

lowerfilter = [value.lower() for value in locfilter]
locname = ' '.join([value for value in l if value.lower() not in lowerfilter])
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现在:

'Portland Oregon'
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  • +1尽管*school*的大写仍然是一个问题. (2认同)